V dot (dv/dt) = (0.5)*(d/dt)*(v^2) ?

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The discussion focuses on the derivation of the equation involving force, mass, and velocity in a physics context. The initial steps involve applying Newton's second law (F=ma) and multiplying by velocity to relate force to power. A key point of confusion is the introduction of the factor of 1/2 in the power equation, which arises from the kinetic energy formula. The clarification provided explains that the derivative of v squared leads to the factor of 2, confirming the relationship between velocity and its derivative. Ultimately, the derivation connects force, power, and kinetic energy in a coherent manner.
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This is not a homework question, but a derivation in my class which I can't get around.

Homework Statement


Step1 F=ma
Step2 \vec{F} = m\frac{d\vec{v}}{dt}
Step3: Multiply both side by v \vec{F}.\vec{v} = m\vec{v}.\frac{d\vec{v}}{dt}
Step4 Power = \frac{d}{dt}\frac{1}{2}m\vec{v}.\vec{v}
Step5 Power = \frac{d}{dt}\frac{1}{2}mv^{2} = \frac{dK}{dt}<br />


Homework Equations



The Attempt at a Solution


I just can't figure out where did the \frac{1}{2} come from in step 4.

Please help & thanks in advance!
 
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v2=v.v

So that d/dt(v2)=2v*dv/dt

They just wrote v2 as v.v
 
rock.freak667 said:
So that d/dt(v2)=2v*dv/dt

Aha, I see.
Or more elaborately:

\frac{d}{dt}v^{2} = \frac{dv}{dt}\frac{d}{dv}v^{2} = \frac{dv}{dt}2v

Thanks rock!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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