- #1
songoku
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- Homework Statement
- The equation 2x^2 - 2(2a + 1)x + a(a - 1) = 0 has two real roots x1 and x2. Find a such that x1 < a < x2 !
- Relevant Equations
- Discriminant
Quadratic formula
For quadratic equation to have two real roots:
b2 - 4ac > 0
(-2 (2a + 1))2 - 4 (2) (a (a - 1)) > 0
4 (4a2 + 4a + 1) - 8a2 + 8a > 0
16a2 + 16a + 4 - 8a2 + 8a > 0
8a2 + 24 a + 4 > 0
2a2 + 6a + 1 > 0
Using quadratic formula, I get a < (-3 - √7) / 2 or a > (-3 + √7) / 2Then how to know if a is between x1 and x2? Thanks
b2 - 4ac > 0
(-2 (2a + 1))2 - 4 (2) (a (a - 1)) > 0
4 (4a2 + 4a + 1) - 8a2 + 8a > 0
16a2 + 16a + 4 - 8a2 + 8a > 0
8a2 + 24 a + 4 > 0
2a2 + 6a + 1 > 0
Using quadratic formula, I get a < (-3 - √7) / 2 or a > (-3 + √7) / 2Then how to know if a is between x1 and x2? Thanks