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1MileCrash
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Homework Statement
What is the vapor pressure of benzene at 50.0 C? Benzene's boiling point is 80.1 C and its heat of vaporization is 31 kJ/mol
Homework Equations
The Attempt at a Solution
I don't want to be that guy who just says "I don't know" but.. All I know is that:
ln P = -(Hvap)/RT + C (and I don't know what C is besides "constant.")
and
ln(p1/p2) = Hvap/R (T1-T2/T1T2) but this relates the vapor pressure at different temperatures..
I am really not good at these applied things... any help is appreciated.