- #1
Liquidxlax
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Homework Statement
I've pretty much solved it, but I'm unsure of my final integration
A uniform chain of length L and density /rho(kg/m) is initially stationary on a horizontal, frictionless table, with part of the chain (length yo) hanging over the edge. How much time passes before the entire chain has left the table?
Homework Equations
arccosh(x) = log(sqrt(x2-1)+x)
The Attempt at a Solution
I don't think i need to put all the work I've done.
my integral
[tex]\int \sqrt{(y^{2}-y^{2}_{o})g/l}^{-1/2}[/tex]
the answer i get is
[tex]arccosh( \sqrt{l/g}*y/y_{o})[/tex]
or
[tex]\sqrt{l/g}*log(2(\sqrt{y^{2}-y^{2}_{o}}+y))[/tex]
yet on wolfram and other websites they say that l/g should not be square rooted. Yet i don't see why.
thanks