Variation of eikonal (phase) set to zero

In summary, the difference between mechanics and optics is that in optics, Fermat's principle is written in analogy with principle of Maupertuis in Classical mechanics (given by \delta S=\delta\int\vec{p}\cdot d\vec{l}=0). In terms of the wave vector it is written as \delta\psi=\delta\int\vec{k}\cdot d\vec{l}=0. Here \psi is known as eikonal (or, phase). Whereas in mechanics, the problem is posed like this: you are to find the desired path by minimizing action...not all paths will lead to the minimum value of action.
  • #1
neelakash
511
1
We know, in optics Fermat's principle is written in analogy with principle of Maupertuis in Classical mechanics (given by [tex]\delta S=\delta\int\vec{p}\cdot d\vec{l}=0[/tex]). In terms of the wave vector it is written as [tex]\delta\psi=\delta\int\vec{k}\cdot d\vec{l}=0[/tex]. Here [tex]\psi[/tex] is known as eikonal (or, phase).

For a monochromatic wave of fixed frequency,[tex]|\vec{k}|=\frac{\omega}{v}=\frac{\omega}{c}\frac{c}{v}=|\vec{k_0}|\frac{c}{v}=|\vec{k_0}|n[/tex] ([tex]n[/tex] is refractive index). Using that the above reduces to
[tex]|\vec{k_0}|\delta\int\ n\ dl=0[/tex] or [tex]\delta\int\ n\ dl=0[/tex] which can be identified as more familiar form of Fermat's principle.[we have calculated the line integral along the direction of [tex]\vec{k}[/tex]]

Notice that it is reached by setting the variation of [tex]\psi[/tex] to zero like in mechanics we have principle of Maupertuis by setting variation of action [tex]S[/tex] equal to zero. It is known that action is minimized in mechanics to get the classical path traced by the system. But is the case same with the phase eikonal also? Landau (section 53-54) identifies [tex]\vec{k}=\nabla\psi[/tex] and thus [tex]\psi[/tex] is a scalar potential of a conservative field. That means whatever path you choose from A to B,the integral [tex]\int_{A}^{B}\vec{k}\cdot\ dl=\int_{A}^{B}|\vec{k}|\ dl[/tex] will remain the same. Anyway, the minimization of optical path is evident from the familiar form of Fermat's principle: [tex]\delta\int\ n\ dl=0[/tex] what can be proved using geometry.

The only difference is that action [tex]S[/tex] is not constrained by any partial differential equation like [tex]\psi[/tex] is. [tex]\psi[/tex] is constrained the eikonal equation given by [tex](\nabla\psi)^2=\ n^2[/tex]-here [tex]n[/tex] is refractive index...Anyway, what I wonder is that whether it is possible to call the problem of optics a variational problem: we are not actually minimizing [tex]\psi[/tex] for [tex]\psi(B)-\psi(A)[/tex] is the same for all the paths...(unless you constrain it via eikonal equation).

Do people know the explanation for it? May be I am missing something...
 
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  • #2
Maupertuis in Classical mechanics

[tex]\delta\int^{t_1}_{t_0}2Tdt=0[/tex]

[tex]2Tdt=m\upsilon^2dt=m\upsilon\upsilondt=pds[/tex]

so

[tex]\delta\int^{M_1}_{M_0}pds=0[/tex]

No scalar product!

Eikonal is solution of equation

[tex](\frac{\partial F}{\partial x})^2+(\frac{\partial F}{\partial y})^2+(\frac{\partial F}{\partial z})^2=\frac{\omega^2}{c^2}n^2(x,y,z)[/tex]

So I think is good to go with Hamilton - Jacobi equation

[tex](\frac{\partial W}{\partial x})^2+(\frac{\partial W}{\partial y})^2+(\frac{\partial W}{\partial z})^2=2m[E-U(\vec{r})]=p^2[/tex]
 
  • #3
Yes...but I did not ask that...what I asked is following:-

In mechanics, the problem is posed like this: you are to find the desired path by minimizing action...not all paths will lead to the minimum value of action.

But in optics, the variational principle [tex]\delta\int\vec{k}\cdot\ d\vec{l}=0[/tex] does NOT minimize the eikonal (for the integral is the same along all the paths).Yet when you reduce this to [tex]\delta\int\ n\ dl=0[/tex],the minimization is apparent...

Why is this difference?
 
  • #4
I do not know why you say there would not be any scalar product...In many texts including Landau the equation is written in terms of scalar product. Only when you choose your contour along the direction of motion,you get cosine term to be unity.
 
  • #5


I would like to provide a response to the content presented above. It is clear that the concept of the eikonal, or phase, is closely related to Fermat's principle in optics. Just like in classical mechanics, where the principle of Maupertuis is derived from the variation of action, in optics we can derive Fermat's principle from the variation of the eikonal.

It is interesting to note that the eikonal can be seen as a scalar potential of a conservative field, with the wave vector being the gradient of the eikonal. This means that the value of the eikonal will be the same for all paths from point A to point B, and the only difference will be in the magnitude of the wave vector. This is similar to the classical mechanics concept, where the action is minimized along the classical path traced by the system.

However, it is important to note that the eikonal is constrained by the eikonal equation, which states that the square of the wave vector is equal to the square of the refractive index. This means that the eikonal cannot take on any arbitrary value, and is instead constrained by this equation. This is different from the action in classical mechanics, which is not constrained by any partial differential equation.

In terms of calling the problem of optics a variational problem, it is important to consider the constraints on the eikonal. While we are not actually minimizing the eikonal itself, the variation of the eikonal is still used to derive Fermat's principle. This can be seen as a constrained variational problem, where the eikonal is constrained by the eikonal equation.

In conclusion, while there are similarities between the eikonal in optics and the action in classical mechanics, there are also important differences to consider, such as the constraints on the eikonal. Understanding these concepts is crucial in furthering our understanding of the principles governing optics and classical mechanics.
 

FAQ: Variation of eikonal (phase) set to zero

1. What is the concept of "variation of eikonal (phase) set to zero"?

The variation of eikonal, also known as the phase, being set to zero refers to a mathematical technique used in optics to simplify the equations for light propagation. It assumes that the phase remains constant throughout the medium, leading to simpler calculations.

2. Why is it important to set the variation of eikonal to zero?

Setting the variation of eikonal to zero allows for easier calculations and analysis of light propagation in a medium. It reduces the complexity of the equations and allows for more accurate predictions of light behavior.

3. What are the limitations of setting the variation of eikonal to zero?

While setting the variation of eikonal to zero can simplify calculations, it is not always an accurate representation of light behavior. In some cases, the phase may vary significantly throughout the medium, leading to errors in predictions. Additionally, this technique cannot be used for all types of light, such as highly focused or tightly confined beams.

4. How is the variation of eikonal set to zero in practice?

The variation of eikonal is typically set to zero by assuming that the phase remains constant throughout the medium. This assumption can be made in certain scenarios, such as in a homogeneous medium or when the light is not tightly focused. In more complex situations, more advanced mathematical techniques may be used to approximate the phase.

5. What are some applications of setting the variation of eikonal to zero?

This technique is commonly used in optics and photonics research to model and predict the behavior of light in various mediums. It has applications in fields such as imaging, microscopy, and laser technology. It is also used in the development of optical components and devices, such as lenses and mirrors.

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