- #1
dramallama
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Homework Statement
A train at a constant 47.0 km/h moves east for 44 min, then in a direction 57.0° east of due north for 27.0 min, and then west for 61.0 min. What are the (a) magnitude (in km/h) and (b) angle (relative to north, with east of north positive and west of north negative) of its average velocity during this trip
Homework Equations
vaverage=displacement/total time
The Attempt at a Solution
For part (a) I found the x and y components of the displacement vector (x-component was 4.2645491 and y-component was 11.51911559056) and I got 12.28317560
Then I plugged that into the vaverage equation:
12.28317560/1.2966=5.59190367 Km/h
I know I got this one right because the wileyplus system game me the checkmark
For part (b)
arctan (4.2645491/11.51911559056)=20.31530698
For this part I keep getting the message that my answer is incorrect, I don't know what I'm doing wrong