Vector diagram - particle collision

In summary, the answer is C because the resultant momentum of both diagrams is in the same direction.
  • #1
jsmith613
614
0

Homework Statement



see attached image

Homework Equations





The Attempt at a Solution



So I know as it is a VECTOR diagram it must either be B or C

So I checked that 1, 2, 3, 4 all pointed in the correct directions and they do in both diagrams.
I chose B (but at random) and the answer was C.
Why is the answer C?

thanks
 

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  • #2
Hi jsmith! :smile:

Use the conservation of momentum, this tells you the initial total momentum should be equal to the final total momentum. In which of the options, do you see this??
 
  • #3
jsmith613 said:

Homework Statement



see attached image

Homework Equations





The Attempt at a Solution



So I know as it is a VECTOR diagram it must either be B or C

So I checked that 1, 2, 3, 4 all pointed in the correct directions and they do in both diagrams.
I chose B (but at random) and the answer was C.
Why is the answer C?

thanks

First of all, is this supposed to be a Classical Mechanics question or a Quantum mechanics question? Because if it is Classical mechanics, then the question is impossible. But in Quantum mechanics, it is possible.
 
  • #4
dimension10 said:
First of all, is this supposed to be a Classical Mechanics question or a Quantum mechanics question? Because if it is Classical mechanics, then the question is impossible. But in Quantum mechanics, it is possible.

? classical mechanism

why is it impossibel?
 
  • #5
jsmith613 said:
? classical mechanism

why is it impossibel?

I'm assuming the mass is constant?
 
  • #6
Infinitum said:
Hi jsmith! :smile:

Use the conservation of momentum, this tells you the initial total momentum should be equal to the final total momentum. In which of the options, do you see this??

momentum is consereved in B??
 
  • #7
jsmith613 said:
momentum is consereved in B??

How is momentum conserved in B :confused:
 
  • #8
dimension10 said:
How is momentum conserved in B :confused:

resultant momentum of both is in the same direciton, no?
 

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  • #9
jsmith613 said:
resultant momentum of both is in the same direciton, no?

In classical mechanics, you have ##m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}## but that does not hold in the question, so I think it is a Quantum mechanics question...
 
  • #10
jsmith613 said:
resultant momentum of both is in the same direciton, no?

Uh nope, it isn't. And you can't be sure about the direction in B as the exact magnitude and direction of original aren't given.

Also, direction isn't the only necessary factor. The magnitude remains same too. Observe C carefully.
 
  • #11
dimension10 said:
In classical mechanics, you have ##m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}## but that does not hold in the question, so I think it is a Quantum mechanics question...

I just reaslied that i have to apply head-to-tail rule
if I apply this it ALWAYS works for ALL questions that have bothered me in the past
:)
 
  • #12
dimension10 said:
In classical mechanics, you have ##m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}## but that does not hold in the question, so I think it is a Quantum mechanics question...

I believe classical mechanics does hold in the question...
 
  • #13
jsmith613 said:
I just reaslied that i have to apply head-to-tail rule

Yes! That's it! :smile:
 
  • #14
Infinitum said:
I believe classical mechanics does hold in the question...

Then I don't think I understood the question properly. What I understand of it is:

$$v_{1i}=1$$
$$v_{2i}=2$$
$$v_{1f}=3$$
$$v_{2f}=4$$
$$m_1,m_2=\mbox{Constant}$$
 
  • #15
dimension10 said:
Then I don't think I understood the question properly. What I understand of it is:

$$v_{1i}=1$$
$$v_{2i}=2$$
$$v_{1f}=3$$
$$v_{2f}=4$$
$$m_1,m_2=\mbox{Constant}$$

You didn't read the question properly o:)

1, 2, 3, 4 are the momenta before and after collision, not the velocities.
 
  • #16
Infinitum said:
You didn't read the question properly o:)

1, 2, 3, 4 are the momenta before and after collision, not the velocities.

Oh! I didn't see that!
 

FAQ: Vector diagram - particle collision

What is a vector diagram?

A vector diagram is a graphical representation of vectors, which are quantities that have both magnitude and direction. It is commonly used in physics to illustrate the motion and interactions of particles.

How is a vector diagram used in particle collision?

In particle collision, a vector diagram is used to represent the initial and final states of the particles involved, as well as the forces acting on them. This allows scientists to analyze the collision and determine the resulting motion and energies of the particles.

What information can be obtained from a vector diagram of a particle collision?

A vector diagram of a particle collision can provide information such as the momentum, velocity, and direction of the particles before and after the collision, as well as the total energy and any changes in energy during the collision.

How is a vector diagram created for a particle collision?

A vector diagram for a particle collision is created by first identifying the initial and final states of the particles, and then drawing vectors to represent their velocities, momenta, and forces. The length and direction of the vectors are determined by the magnitudes and directions of these quantities.

What are the limitations of using a vector diagram to analyze particle collisions?

A vector diagram can only provide an approximation of the motion and interactions of particles during a collision, as it does not take into account factors such as air resistance and other external forces. Additionally, the accuracy of the diagram depends on the precision of the measurements and calculations used to create it.

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