Velocities of four masses | Conservation of Momentum

  • #1
I_Try_Math
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Homework Statement
Three 70-kg deer are standing on a flat 200-kg rock that is on an ice-covered pond. A gunshot goes off and the deer scatter, with deer A running at ##(15\hat{i} + 5\hat{j})\frac{m}{s}##, deer B running at ##(-12\hat{i} + 8\hat{j})\frac{m}{s}##, and deer C running at ##(1.2\hat{i} - 18\hat{j})\frac{m}{s}##. What is the velocity of the rock on which they were standing?
Relevant Equations
##\rho_i=\rho_f##
##\vec{\rho_{D1,i}}+\vec{\rho_{D2,i}}+\vec{\rho_{D3,i}}+\vec{\rho_{R,i}} = \vec{\rho_{D1,f}} +\vec{\rho_{D2,f}} +\vec{\rho_{D3,f}} +\vec{\rho_{R,f}}##
##\vec{0} = \vec{\rho_{D1,f}} +\vec{\rho_{D2,f}} +\vec{\rho_{D3,f}} +\vec{\rho_{R,f}}##
##\vec{0} = m_D(15\hat{i} + 5\hat{j}) + m_D(-12\hat{i} + 8\hat{j}) + m_D(1.2\hat{i} - 18\hat{j}) + m_R\vec{v_{f,R}} ##
##\vec{0} = m_D((15\hat{i} + 5\hat{j}) + (-12\hat{i} + 8\hat{j}) + (1.2\hat{i} - 18\hat{j})) + m_R\vec{v_{f,R}}##
##\vec{0} = m_D(4.2\hat{i}-5\hat{j}) + m_R\vec{v_{f,R}}##
##\vec{0} = (294\hat{i}-350\hat{j}) + 200\vec{v_{f,R}}##
##(-294\hat{i}+350\hat{j}) = 200\vec{v_{f,R}}##
##\vec{v_{f,R}} = (-1.47\hat{i}+1.75\hat{j})\frac{m}{s}##

Textbook says the correct answer is ## (-0.21\hat{i} + 0.25\hat{j})\frac{m}{s}##. Are my assumptions with respect to how conservation of momentum works in this case wrong? Any help is appreciated.
 
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  • #2
Hmm... The "correct answer" would work for three 10-kg deer.
 
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  • #3
Hill said:
Hmm... The "correct answer" would work for three 10-kg deer.
Ah thank you. Kept thinking I was making an algebra error or something. The answer key's probably wrong. Wouldn't be the first time.
 
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  • #4
I_Try_Math said:
Relevant Equations: ##\rho_i=\rho_f##
For future reference, the conventional symbol for momentum is the Latin ##p## (pee) not the Greek ##\rho## (rho). Please use the correct symbol to avoid confusion.
 
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  • #5
kuruman said:
For future reference, the conventional symbol for momentum is the Latin ##p## (pee) not the Greek ##\rho## (rho). Please use the correct symbol to avoid confusion.
I was not aware of that. Thank you for pointing that out.
 
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  • #6
Whoever made up this question has been stuck in an office for too long!
 
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  • #7
PeroK said:
Whoever made up this question has been stuck in an office for too long!
Armchair deer hunter? At least the question wasn't "Find the direction the gunshot came from", the intended answer being a unit vector in the direction of the velocity of the CM of the deer.
 
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  • #8
kuruman said:
Armchair deer hunter?
Na, this is someone who is completely imagining what it's like to hunt deer. To your comment, he shot at the middle of them... :woot:.

Clearly the (wild) gun shot trigged a landslide. The deer rode the rock down the mountain side landing them in the middle of a frozen pond...stunned. When the ice cracked underneath them, they jumped off the boulder.
 
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FAQ: Velocities of four masses | Conservation of Momentum

What is the principle of conservation of momentum?

The principle of conservation of momentum states that in a closed system with no external forces, the total momentum of the system remains constant. This means that the sum of the momenta of all objects before an interaction must equal the sum of the momenta of all objects after the interaction.

How do you calculate the momentum of an object?

Momentum (p) of an object is calculated using the formula p = mv, where m is the mass of the object and v is its velocity. The momentum is a vector quantity, meaning it has both magnitude and direction.

How do you apply conservation of momentum to a system with four masses?

To apply conservation of momentum to a system with four masses, you need to ensure that the total momentum before any interaction is equal to the total momentum after the interaction. This involves summing the individual momenta (mass times velocity) of all four masses before and after the event and setting these sums equal to each other.

What happens to the velocities of the masses after a collision?

The velocities of the masses after a collision depend on the type of collision (elastic or inelastic) and the initial conditions (masses and velocities) of the system. In an elastic collision, both momentum and kinetic energy are conserved. In an inelastic collision, only momentum is conserved, and the objects may stick together or deform, resulting in a loss of kinetic energy.

Can you provide an example problem involving four masses and conservation of momentum?

Sure! Consider four masses m1, m2, m3, and m4 with initial velocities v1, v2, v3, and v4. If these masses collide and their final velocities are v1', v2', v3', and v4', the conservation of momentum principle states that m1v1 + m2v2 + m3v3 + m4v4 = m1v1' + m2v2' + m3v3' + m4v4'. By solving this equation, you can determine the final velocities if the initial conditions and the type of collision are known.

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