- #1
ptptaylor
- 7
- 0
Hi,
I am becoming a bit stuck with a fairly cynical question.
I want to work out the velocity of the fluid from the static and total pressures obtained in a wind tunnel experiment.
The manometor was open to air (atmospheric) at one end and measuring static or total pressure at the other. Both readings were taken.
To calculate the velocity p0=p+0.5*rho*u2
Which all seems fine.
Rearrange to find u
However, the values I have are not Ptotal or Pstatic correct?
I need to add atmospheric pressure to these?
I have an equation which is:
P0=patm-rho*g*h
So for an example,
patm=101081.39 Pa
h? (Reading from manometor)=0.002
So:
101081.39-(1.2*9.81*0.002)=P0
Would this indeed be the total pressure?
Paul
I am becoming a bit stuck with a fairly cynical question.
I want to work out the velocity of the fluid from the static and total pressures obtained in a wind tunnel experiment.
The manometor was open to air (atmospheric) at one end and measuring static or total pressure at the other. Both readings were taken.
To calculate the velocity p0=p+0.5*rho*u2
Which all seems fine.
Rearrange to find u
However, the values I have are not Ptotal or Pstatic correct?
I need to add atmospheric pressure to these?
I have an equation which is:
P0=patm-rho*g*h
So for an example,
patm=101081.39 Pa
h? (Reading from manometor)=0.002
So:
101081.39-(1.2*9.81*0.002)=P0
Would this indeed be the total pressure?
Paul