Velocity given centripetal force, accounting for friction

In summary, the conversation discusses the calculation of velocity in a circular path, taking into account friction. Two scenarios are considered - one where the radius is kept constant and the other where the frictional force is proportional to the square of the velocity. The formula for exponential decay is mentioned, along with the case of a constant force pulling an object towards the center of the circle. The effects of friction on the object's speed are also discussed.
  • #1
moonman239
282
0
Hello,

I would like to know how to calculate the velocity of an object in a circular path, accounting for friction. I know that in a frictionless environment, the equation for the velocity is v2=F*R/M.
 
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  • #2
If you introduce friction into this scenario, then the object will no longer move in a circle because its velocity will decrease. This would result in the value of R having to decrease if you keep F constant. The object would spiral towards the centre of the circle.
If you keep R constant then you would need to reduce F to maintain circular motion.
Are you considering either of these scenarios?
Perhaps you could just elaborate a little on what you are thinking of.
 
  • #3
Okay, then let's say that I'm keeping R constant.
 
  • #4
Then what's the formula?
 
  • #5
moonman239 said:
Okay, then let's say that I'm keeping R constant.

You haven't specified the kind of friction.
As a crude approximation you can use a friction that is proportional to velocity.

The next step is to work out the velocity as a function of time in the case of deceleration with a linear-to-velocity friction. If the velocity is halved the frictional force is halved; the velocity will decay. That is, in the crude approximation with a linear-to-velocity friction the velocity as a function of time will be exponential decay.

The general formula for a function that describes exponential decay is as follows:

[tex] y = e^{-x} [/tex]

If the specification is that R must remain the same throughout then the centripetal force must be adjusted all the time to the current velocity. Alternatively, you can opt to use as approximation that the frictional force is proportional to the square of the velocity.

But demanding that R remains the same gives a physics problem that is rather uninteresting. In essence the problem is the same as the case of linear motion.


What if the centripetal force is not adjusted, but a constant force? For example, take the case of an object sliding over a surface, with a chord tugging at it, with the chord running over a pulley, and at the other end a weight.

Then as the object slows down the centripetal force start reeling it in, and in the process of being pulled closer to the center the speed tends to increase again. What happens then can't be expressed with just a simple expression.
 

FAQ: Velocity given centripetal force, accounting for friction

What is centripetal force?

Centripetal force is the force that acts on an object moving in a circular path, directed towards the center of the circle.

What role does friction play in calculating velocity in this scenario?

Friction is a force that opposes motion and it can affect the velocity of an object moving in a circular path by reducing its speed.

How does centripetal force relate to velocity?

Centripetal force and velocity are directly proportional - an increase in centripetal force will result in an increase in velocity.

What is the formula for calculating velocity given centripetal force?

The formula for calculating velocity given centripetal force is v = √(F_c/m), where v is velocity, F_c is centripetal force, and m is the mass of the object.

How does the mass of the object affect the velocity given centripetal force?

The mass of the object is inversely proportional to velocity - as the mass increases, the velocity decreases, and vice versa.

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