Velocity of SHM Object at t=0.10s

In summary, the conversation discusses the formula for the velocity of an object undergoing simple harmonic motion at the end of a spring, where the mass, spring constant, and maximum distance are given. The formula is v=A*√K/m*cos(√K/m *t), with t=0.10s, m=36.0g, k=400g/s^2, and A=5.0 cm.
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Homework Statement


At time t, the velocity of v of an object undergoing simple harmonic motion at the end of a spring is given by the formula below. here m is mass of the object (in g), k is a constant depending on the spring (in g/s squared), a is the maximum distance the object moves and t is time (in s).

t=0.10s
m= 36.0g
k= 400g/s][2]
A= 5.0 cm

Homework Equations


v=A*√K/m*cos(√K/m *t)

The Attempt at a Solution

 
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You have a formula for the velocity and the values of all the variables. So what's your attempt at a solution?
 

FAQ: Velocity of SHM Object at t=0.10s

What is the definition of SHM?

SHM stands for Simple Harmonic Motion. It is a type of periodic motion in which the object moves back and forth along a straight line, with a constant amplitude and a constant period.

What is the formula for the velocity of an SHM object at t=0.10s?

The formula for the velocity of an SHM object at t=0.10s is v = Aωsin(ωt + ϕ), where A is the amplitude, ω is the angular frequency, t is the time, and ϕ is the phase angle.

How does the velocity of an SHM object change over time?

The velocity of an SHM object is constantly changing as it moves back and forth. At the equilibrium point (where the displacement is 0), the velocity is at its maximum. As the object moves away from the equilibrium point, the velocity decreases until it reaches 0 at the maximum displacement. It then increases in the opposite direction until it reaches its maximum again at the equilibrium point.

What factors affect the velocity of an SHM object?

The velocity of an SHM object is affected by the amplitude, mass, and spring constant of the system. A larger amplitude will result in a higher velocity, while a larger mass or spring constant will result in a lower velocity.

How is the velocity of an SHM object related to its acceleration?

The velocity and acceleration of an SHM object are related by the equation a = -ω²x, where a is the acceleration, ω is the angular frequency, and x is the displacement. This means that the acceleration is directly proportional to the displacement and inversely proportional to the square of the angular frequency.

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