Velocity squared veurses distance

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In summary, the conversation is about calculating the maximum velocity and distance traveled of a mass at the bottom of a pendulum with various amplitudes. The task is to graph the maximum velocity squared versus distance and interpret the graph. The physical value of the graph is unknown, but it could represent maximum acceleration over a distance.
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enthdegree
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Homework Statement



I've calculated the maximum velocity of a mass at the bottom of a pendulum given various amplitudes. I've also gotten the distance that mass falls from it's angle furthest from the extreme to it's lowest point.
I'm being asked to graph the maximum velocity squared vs the distance traveled for a bunch of increasing amplitudes and then interpret that graph.

The graph appears to be linear but I have no idea what physical value it could represent. We have not yet learned in physics what m^2/t^2 values represent over m. Could it be maximum accelleration>>?

It'd be great if someone could clear this up for me, thanks!
 
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enthdegree said:

Homework Statement



I've calculated the maximum velocity of a mass at the bottom of a pendulum given various amplitudes. I've also gotten the distance that mass falls from it's angle furthest from the extreme to it's lowest point.
I'm being asked to graph the maximum velocity squared vs the distance traveled for a bunch of increasing amplitudes and then interpret that graph.

The graph appears to be linear but I have no idea what physical value it could represent. We have not yet learned in physics what m^2/t^2 values represent over m. Could it be maximum accelleration>>?

It'd be great if someone could clear this up for me, thanks!
By equating maximum potential energy (v=0) to maximum kinetic energy (h=0) we have:

v^2 = 2gh

where h is the maximum height. So v^2 represents an acceleration x distance (potential energy / unit mass).

AM
 

FAQ: Velocity squared veurses distance

What is the equation for velocity squared versus distance?

The equation for velocity squared versus distance is V2 = u2 + 2as, where V is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.

How is velocity squared versus distance related to motion?

Velocity squared versus distance is a mathematical representation of the relationship between velocity and distance in an object's motion. It shows how velocity changes as an object moves a certain distance, taking into account any initial velocity and acceleration.

Can velocity squared versus distance be used for all types of motion?

Yes, the equation for velocity squared versus distance can be used for any type of motion, as long as there is a constant acceleration. This includes motion in a straight line, circular motion, and projectile motion.

What is the significance of velocity squared versus distance in physics?

Velocity squared versus distance is important in physics because it helps us understand the relationship between an object's velocity and distance traveled. It is also a key component in the study of motion and can be used to make predictions about an object's future motion.

How is velocity squared versus distance used in real-world applications?

The equation for velocity squared versus distance is used in various real-world applications, such as calculating the speed of a car during a race, determining the distance a ball will travel when thrown, and understanding the motion of satellites in orbit. It is also used in engineering and design to ensure the safety and efficiency of moving objects.

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