- #1
fonz
- 151
- 5
Just simply, from the diagram above is p1=p3 and v1=v3?
Thanks
Dan
If the flow is inviscid, then the inner flow at section 3 can't be determined. With zero viscosity, there's no reason that the flow from section 2 couldn't simply continue with the same diameter as the tube in section 2, flowing at v2 while the surrounding fluid in section 3 isn't moving at all, since there's no interaction between shear boundaries with an inviscid flow. The "average" net flow v3 should be the same as v1 since mass flow is constant, assuming section 3 diameter is the same as section 1 diameter.cjl said:If the cross sectional areas are the same and the flow is inviscid, then yes.
The Venturi Principle is a scientific concept that states that as the velocity of a fluid increases, the pressure decreases.
The Venturi Principle works by using a constricted tube or pipe to accelerate the fluid, which causes a decrease in pressure according to Bernoulli's principle. The pressure then returns to its original level after the fluid leaves the constriction.
Yes, according to the Venturi Principle, the pressure (p) at the entrance (1) and exit (3) of the constriction should be equal, as well as the velocity (v) at these points.
The Venturi Principle has many practical applications, such as in carburetors, where it is used to mix air and fuel in the correct ratio for combustion. It is also used in respiratory devices, water filtration systems, and even musical instruments.
While the Venturi Principle is a useful concept, it does have some limitations. It assumes that the fluid is incompressible and that there is no turbulence present. In reality, these conditions may not always be met, leading to discrepancies in the predicted pressure and velocity values.