Vertical circular motion

In summary, vertical circular motion refers to the movement of an object in a circular path while moving vertically, influenced by gravitational forces. This motion involves varying speeds and accelerations as the object experiences different forces at different points in the circle. Key concepts include centripetal force, which keeps the object in circular motion, and the effects of gravitational force, particularly at the top and bottom of the circular path. Understanding this motion is essential in physics and engineering, especially in analyzing systems like roller coasters and pendulums.
  • #1
sdfsfasdfasf
75
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Homework Statement
x
Relevant Equations
x
So far I believe that speed changes during vertical circular motion, and its very hard to get uniform circular motion that is in the vertical plane.
This is because there is a difference in vertical height between the bottom/top of the circle so at the top the object must have done work against gravity (and hence slowed down). I have found this page http://hyperphysics.phy-astr.gsu.edu/hbase/Mechanics/cirvert.html which furthers my belief that this is true.

However I keep on seeing different authors and youtube videos where people write down something like "N - mg = Fc at min" and "mg - N = Fc" at max, this doesn't sit right with me because the two v variables are clearly different (unless the object is truly staying at a constant speed, is that even possible in vertical motion?), so the two equations look like rubbish.

Can someone help me out and convince me I have the right idea? If not then I'd love to be told where my mistakes are.
Thank you! My physics course only covers horizontal uniform circular motion but they can always add an extension question where gravity is involved. Thanks.
 
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  • #2
sdfsfasdfasf said:
Homework Statement: x
Relevant Equations: x

So far I believe that speed changes during vertical circular motion, and its very hard to get uniform circular motion that is in the vertical plane.
Speed can change during circular motion around a horizontal axis. But it need not do so.

Consider, for example, a bug of negligible mass clinging to the side of a rotating wheel. If the wheel rotates at a uniform rate, the bug will travel in uniform circular motion. If you complain that the wheel is slightly unbalanced due to the presence of the bug, add a second bug positioned opposite the first.

Yes, if you are swinging a sling stone at the end of its strap in a vertical circle then the speed of the stone at the top of the arc will almost certainly be lower than its speed at the bottom. In the absence of non-gravitational tangential force, we can quantify this speed difference by making an energy argument like the one you propose. In the case of a bug on a wheel, there will be tangential force from the tire on the bug to preserve the uniform rotation.
sdfsfasdfasf said:
However I keep on seeing different authors and youtube videos where people write down something like "N - mg = Fc at min" and "mg - N = Fc" at max, this doesn't sit right with me because the two v variables are clearly different
Neither of the formulas that you quote here involve ##v##. You need to work harder to make a coherent claim.
 
  • #3
Even in the case of non-uniform circular motion, the centripetal acceleration is ##v^2/r##. The difference being that there is also a tangential force component and that ##v## is variable because of this.
 
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  • #4
sdfsfasdfasf said:
However I keep on seeing different authors and youtube videos where people write down something like "N - mg = Fc at min" and "mg - N = Fc" at max, this doesn't sit right with me because the two v variables are clearly different (unless the object is truly staying at a constant speed, is that even possible in vertical motion?), so the two equations look like rubbish.
They would be rubbish if the N and Fc are supposed to be constants, or if they are supposed to be scalar variables with consistent sign convention.
And I think you meant and "mg + N = Fc" at max.

##\vec F_{net}= -mg\hat y+ \vec N##, where ##\vec F_{net}## and ##\vec N## are functions of the angle.
Centripetal force is the radially inward component of the net force and ##\vec N=-N\hat r##:
##F_c=- \vec F_{net}\cdot \hat r=mg\hat y\cdot \hat r-\vec N\cdot\hat r =mg\hat y\cdot \hat r+N##
where ##N## and ##F_c## are magnitudes.
At the top, ##F_c=mg+N##
At the bottom, ##F_c=-mg+N##.
 
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  • #5
sdfsfasdfasf said:
However I keep on seeing different authors and youtube videos where people write down something like "N - mg = Fc at min" and "mg - N = Fc" at max, this doesn't sit right with me because the two v variables are clearly different (unless the object is truly staying at a constant speed, is that even possible in vertical motion?), so the two equations look like rubbish.
For a constant radius, the value of N in each case depends on the square of the tangential velocity, which evidently shows the greatest value where most of the potential energy has became kinetic energy.

Note that this is applicable to a system using only its initial mechanical energy to complete the vertical loop (a roller coaster car, for example).
It is different for self-propelled bodies that can regulate the tangential velocity (acrobatic airplane, for example).

Please, see:
https://www.physicsclassroom.com/mmedia/circmot/rcd.cfm

https://britishaerobaticacademy.com/how-to-fly-a-loop/

🛩️

rcd.gif
 
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  • #6
Orodruin said:
Even in the case of non-uniform circular motion, the centripetal acceleration is ##v^2/r##. The difference being that there is also a tangential force component and that ##v## is variable because of this.
So the resultant (centripetal) force varies, correct? As the velocity's magnitude varies throughout the loop.
 
  • #7
sdfsfasdfasf said:
So the resultant (centripetal) force varies, correct? As the velocity's magnitude varies throughout the loop.
Yes. The centripetal component of the resultant force varies with the velocity speed.
 
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  • #8
sdfsfasdfasf said:
So the resultant (centripetal) force varies, correct? As the velocity's magnitude varies throughout the loop.
Sure, as long as speed varies. As mentioned, if there is self-propellment or similar, it is possible to keep speed constant as well and then the centripetal acceleration does not vary.
 
  • #9
Wonderful, thank you so much, Orodruin.
 

FAQ: Vertical circular motion

What is vertical circular motion?

Vertical circular motion refers to the motion of an object that moves in a circular path while being subjected to gravitational forces. This type of motion is characterized by the object moving along a vertical circle, such as a pendulum swinging or a roller coaster looping. The forces acting on the object, including tension, gravity, and centripetal force, vary depending on the object's position in the circular path.

What forces act on an object in vertical circular motion?

In vertical circular motion, the primary forces acting on the object include gravitational force, tension (if applicable), and centripetal force. Gravity acts downward, while tension can act along the path of the motion, particularly in cases like a string or rod. The centripetal force, which is required to keep the object moving in a circular path, is provided by the net force acting towards the center of the circle, which is the result of the combination of these forces.

How does speed affect vertical circular motion?

The speed of an object in vertical circular motion significantly influences the forces acting on it. At the top of the circular path, the object needs to maintain a minimum speed to ensure that gravitational force is sufficient to provide the necessary centripetal force. If the speed is too low, the object may lose contact with the circular path. Conversely, at the bottom of the circular path, the speed increases the tension in the string or rod, which must counteract both gravity and provide the centripetal force required for circular motion.

What is the minimum speed required at the top of a vertical circle?

The minimum speed required at the top of a vertical circle can be derived from the balance of forces. At the top, the gravitational force must provide the necessary centripetal force to keep the object moving in a circle. The formula for the minimum speed (v) at the top is given by v = √(g*r), where g is the acceleration due to gravity and r is the radius of the circle. This speed ensures that the object maintains contact with the circular path without falling.

How can energy conservation be applied to vertical circular motion?

Energy conservation principles can be applied to vertical circular motion by considering the conversion between potential and kinetic energy. At the highest point of the motion, the object has maximum potential energy and minimum kinetic energy. As it descends, potential energy is converted into kinetic energy, increasing the object's speed. At the lowest point, the kinetic energy is maximized while potential energy is minimized. The total mechanical energy remains constant, assuming no energy losses due to friction or air resistance.

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