- #1
Dvsdvs
- 24
- 0
this is a very quick question. my teacher wants me to prove that
((kq)/(sqroot(x^2+y^2+z^2))) (x,y,z) is conservative. by this does it mean that
F=((kq)/(sqroot(x^2+y^2+z^2)))i+((kq)/(sqroot(x^2+y^2+z^2)))j+((kq)/(sqroot(x^2+y^2+z^2)))k
or does it she mean that
F=((kq)/(sqroot(x^2+y^2+z^2)))Xi+((kq)/(sqroot(x^2+y^2+z^2)))Yj+((kq)/(sqroot(x^2+y^2+z^2)))Zk
Basically I am asking if that (x,y,z) is being distrubuted or its just acting as the (i,j,k) itself Thank you very much
Edit oops, forgot the ^3 power in the denominator. But you guys get the point
((kq)/(sqroot(x^2+y^2+z^2))) (x,y,z) is conservative. by this does it mean that
F=((kq)/(sqroot(x^2+y^2+z^2)))i+((kq)/(sqroot(x^2+y^2+z^2)))j+((kq)/(sqroot(x^2+y^2+z^2)))k
or does it she mean that
F=((kq)/(sqroot(x^2+y^2+z^2)))Xi+((kq)/(sqroot(x^2+y^2+z^2)))Yj+((kq)/(sqroot(x^2+y^2+z^2)))Zk
Basically I am asking if that (x,y,z) is being distrubuted or its just acting as the (i,j,k) itself Thank you very much
Edit oops, forgot the ^3 power in the denominator. But you guys get the point
Last edited: