Very silly question on whether the domain of ##log_{10}(x²)## = ##2log_{10}(x)##

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In summary, the equation ##log_{10}(x²) = 2log_{10}(x)## is valid for all positive values of x, as both expressions represent the logarithm of x squared. The question highlights a basic property of logarithms, specifically the power rule, which states that the logarithm of a power can be expressed as the exponent times the logarithm of the base. Therefore, the domain of both expressions is x > 0.
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tellmesomething
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Homework Statement
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So say I have to find the x intercept of this function $$log_{10}(x²)$$ I get x={-1,1}.
But if I try to find the x intercept of this same function after simplifying I get $$2log_{10} (x)$$ I get x={1}
 
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tellmesomething said:
Homework Statement: Title
Relevant Equations: Title

So say I have to find the x intercept of this function $$log_{10}(x²)$$ I get x={-1,1}.
But if I try to find the x intercept of this ## same function## after simplifying I get $$2log_{10} (x)$$ I get x={1}
After simplifying, you get ##2log_{10} (|x|)## rather than ##2log_{10} (x)##, which has the same intercept as the original function.
 
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Hill said:
After simplifying, you get ##2log_{10} (|x|)## rather than ##2log_{10} (x)##, which has the same intercept as the original function.
Okay then :-)
 

FAQ: Very silly question on whether the domain of ##log_{10}(x²)## = ##2log_{10}(x)##

What is the domain of the function log10(x²)?

The domain of the function log10(x²) is all real numbers except zero. Since the logarithm is only defined for positive arguments, x² must be greater than zero, which means x can take any value except zero (x ≠ 0).

Is log10(x²) equal to 2log10(x)?

Yes, log10(x²) is equal to 2log10(x) for x > 0. This is due to the logarithmic property that states logb(an) = n * logb(a).

What is the domain of the expression 2log10(x)?

The domain of the expression 2log10(x) is x > 0. The logarithm is only defined for positive values of x, so the expression is only valid when x is greater than zero.

Are there any restrictions on x for the equation log10(x²) = 2log10(x)?

Yes, for the equation log10(x²) = 2log10(x) to hold true, x must be greater than zero. Both sides of the equation involve logarithms, which require positive arguments.

What happens if x is negative or zero in the equation log10(x²) = 2log10(x)?

If x is negative or zero, the equation log10(x²) = 2log10(x) is undefined. Logarithms of non-positive numbers are not defined in the real number system, so the equation cannot be evaluated in those cases.

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