VI Characteristic of Circuit - Solving for X, R1-R6

[abeltyukov]

Homework Statement

Hi,

I have the following circuit: http://i137.photobucket.com/albums/q208/infinitbelt/ProblemSet3Circuit1.png"

Also, the following is known:
X=60 V
R1= 10 Ω
R2= 20 Ω
R3= 10 Ω
R4=5 Ω
R5=20 Ω
R6 = 5 Ω

Homework Equations

V = IR
y = mx + b

The Attempt at a Solution

How do I go about finding a V-I characteristic of this circuit? I know that the slope of the graph is the resistance but I am confused as to how to start this one. I found the resistance across the source by using circuit reduction. I got that to be 32 ohms. So is the V-I characteristic just V = 32i? or is it just a constant line y = 60? (in this case V is on the y-axis and I is on the x-axis)


Thanks!

 

[CEL]

Homework Statement

Hi,

I have the following circuit: http://i137.photobucket.com/albums/q208/infinitbelt/ProblemSet3Circuit1.png"

Also, the following is known:
X=60 V
R1= 10 Ω
R2= 20 Ω
R3= 10 Ω
R4=5 Ω
R5=20 Ω
R6 = 5 Ω

Homework Equations

V = IR
y = mx + b

The Attempt at a Solution

How do I go about finding a V-I characteristic of this circuit? I know that the slope of the graph is the resistance but I am confused as to how to start this one. I found the resistance across the source by using circuit reduction. I got that to be 32 ohms. So is the V-I characteristic just V = 32i? or is it just a constant line y = 60? (in this case V is on the y-axis and I is on the x-axis)Thanks!

Homework Statement

Homework Equations

The Attempt at a Solution

You can consider the voltage source X as a resistor with zero resistance. It's characteristic is a line parallel to the I axis, passing through V = 60.
X is in series with R1 and R2, so you can associate their characteristics.
Since this sub circuit is in parallel with R3, you can now associate their characteristics.
The resultant characteristic is associated with R4 and R5 which are in series and finally that characteristic is associated with R6 in parallel.

 

[piercas]

I would first clarify the question and make sure I have all the necessary information to solve for the V-I characteristic of this circuit. Is the goal to find the overall resistance of the circuit or to plot the V-I characteristic graph? If it is to plot the graph, we need to know the value of the voltage source as well as the values of the resistors R1-R6.

Assuming the goal is to plot the V-I characteristic graph, we can use Ohm's law (V = IR) to calculate the voltage drop across each resistor. Using the given values, we can calculate the voltage drop across each resistor as follows:

V1 = (10 Ω)(I)
V2 = (20 Ω)(I)
V3 = (10 Ω)(I)
V4 = (5 Ω)(I)
V5 = (20 Ω)(I)
V6 = (5 Ω)(I)

Next, we can use Kirchoff's Voltage Law (KVL) to find the total voltage across the circuit. This can be done by summing up the voltage drops across each resistor:

Vtotal = V1 + V2 + V3 + V4 + V5 + V6

Substituting the calculated values, we get:

Vtotal = (10 Ω)(I) + (20 Ω)(I) + (10 Ω)(I) + (5 Ω)(I) + (20 Ω)(I) + (5 Ω)(I)
Vtotal = (70 Ω)(I)

Now, we can plot the V-I characteristic graph with voltage (Vtotal) on the y-axis and current (I) on the x-axis. The slope of this graph will be the resistance of the circuit, which we can calculate by rearranging the equation to solve for I:

I = Vtotal / (70 Ω)

Therefore, the slope (resistance) of the V-I characteristic graph will be:

R = 70 Ω

In conclusion, the V-I characteristic of this circuit can be represented by a straight line with a slope of 70 Ω and a y-intercept of 0 (since there is no voltage drop at 0 current). The equation for this line would be y = 70x, where y represents voltage and x represents current. I hope this helps!