- #1
Ammar w
- 28
- 0
Homework Statement
Hi,
We have this cut. :
and in the image below, I10 is calculated by using current division :
The Attempt at a Solution
I tried to find it using voltage division but the answer is wrong :
Vx(of the upper node) = 100 * [tex]\frac{j5}{4+j5}[/tex] = 60.98 + j48.78 V
=> I10 = [tex]\frac{Vx}{10 - j5}[/tex] = 2.93 + 6.34 = 6.98 [itex]\ 65.2[/itex]
which is wrong, WHY?
thanks