- #1
twoducks
- 5
- 0
Hey there, newbie here. =)
ive been reading up/pondering on electrical phenomenon recently and I am still working out the conceptual constructs in my head - which brings me here!
the issue I am wrestling with today is how, as i understand it, different amounts of energy can be moved with a static frequency and voltage (and presumably static speed of wave propagation?).
so i got my 110v 60hz(where i live) AC current coming out of the wall(well jiggling out / in i suppose).
but different devices draw different amounts of current from this source.
it seems contrary to my sense of reason that, based on a static amplitude(voltage) and a static frequency (60hz in this case) at a static rate of wave propagation, to be able to move different amounts of energy.
so how can i conceptualize the mechanism by which the refrigerator "uses" more power than the clock on my desk?
i realize there is a factor which i neglected to mention that is resistance. and i have read that less resistance = more current. (I=v/r)
however i am not able to reconcile, for example, how the utility company can charge more to run a refrigerator than a clock if the signal they send is the same for both.
-two ducks
ive been reading up/pondering on electrical phenomenon recently and I am still working out the conceptual constructs in my head - which brings me here!
the issue I am wrestling with today is how, as i understand it, different amounts of energy can be moved with a static frequency and voltage (and presumably static speed of wave propagation?).
so i got my 110v 60hz(where i live) AC current coming out of the wall(well jiggling out / in i suppose).
but different devices draw different amounts of current from this source.
it seems contrary to my sense of reason that, based on a static amplitude(voltage) and a static frequency (60hz in this case) at a static rate of wave propagation, to be able to move different amounts of energy.
so how can i conceptualize the mechanism by which the refrigerator "uses" more power than the clock on my desk?
i realize there is a factor which i neglected to mention that is resistance. and i have read that less resistance = more current. (I=v/r)
however i am not able to reconcile, for example, how the utility company can charge more to run a refrigerator than a clock if the signal they send is the same for both.
-two ducks