Volume enclosed by isosurfaces in electrostatics

In summary, the conversation discusses the computation of the perimeter and surface enclosed by an equipotential line of electrostatic potential in a plane with N points, each with a charge contributing to the Coulomb potential. The potential is given by phi=1/r for a single point, and phi=1/r1+1/r2+1/r3+...+1/rN for multiple points. The perimeter and surface can be easily calculated for a single point, but for multiple points, the equipotential line becomes a set of deformed circles around isolated points and merged circles around points that are not sufficiently isolated. The generalisation of this problem to 3D is similar.
  • #1
woertgner
2
0
Imagine that you have N points scattered in the plane. Each point is charged and contributes to the total potential the same Coulomb potential proportional to 1/r. Now consider some equipotential line of the total electrostatic potential. Is there an analytical expression for the surface enclosed by this line and for the length of this line?
 
Physics news on Phys.org
  • #2
woertgner said:
Imagine that you have N points scattered in the plane. Each point is charged and contributes to the total potential the same Coulomb potential proportional to 1/r. Now consider some equipotential line of the total electrostatic potential. Is there an analytical expression for the surface enclosed by this line and for the length of this line?
If you are saying you want to find out the area enclosed by this line then by simple geometry you know the circle has maximum area.
The potential due to a sheet is diectly proportional to r.
that due to line is proportional to ln(r)
You wrote about the "volume" enclosed by isosurfaces
 
  • #3
I am not sure if I understood your answer. I rephrase my question in more detail. Imagine you have one charged point in the plane. The electrostatic potential due to this point charge is up to a multiplicative factor: phi=1/r. Consider an equipotential line by setting phi=c. This equipotential line clearly is a circle and it is easy to compute its perimeter and surface. Now consider two equally charged points in the plane. The electrostatic potential due to these two charged points is up to a multiplicative factor phi=1/r1+1/r2, where r1 is the distance from the first point and r2 is the distance from the second one. Consider an equipotential line again by setting phi=c. If c is small enough you obtain two slightly deformed circles, if c is larger you obtain two merged circles forming something like number eight. How to compute the perimeter and surface now? What about a general case when we have N points in the plane and the potential is given by phi=1/r1+1/r2+1/r3+...+1/rN? By setting phi=c we obtain a set of deformed circles around points, which are sufficiently far away from other points and merged circles from others that are not sufficiently isolated. How to compute the perimeter and surface now? The generalisation of this problem to 3D is similar.
 

FAQ: Volume enclosed by isosurfaces in electrostatics

What is the significance of the volume enclosed by isosurfaces in electrostatics?

The volume enclosed by isosurfaces in electrostatics represents the region in space where the electric field has a constant magnitude. This is important in understanding the distribution of charges and the behavior of electric fields.

How is the volume enclosed by isosurfaces calculated?

The volume enclosed by isosurfaces is calculated by first determining the isosurface value, which is the electric field magnitude at which the isosurface is drawn. Then, the volume is calculated by integrating the electric field magnitude over the isosurface.

How does the volume enclosed by isosurfaces relate to the electric field strength?

The volume enclosed by isosurfaces is directly related to the electric field strength. As the electric field strength increases, the volume enclosed by isosurfaces also increases. This is because a stronger electric field will have a larger region where the electric field magnitude is constant.

Can the volume enclosed by isosurfaces change?

Yes, the volume enclosed by isosurfaces can change. It is dependent on the distribution of charges and the strength of the electric field. If the distribution of charges or the electric field strength changes, the volume enclosed by isosurfaces will also change.

What is the practical application of understanding the volume enclosed by isosurfaces?

Understanding the volume enclosed by isosurfaces is important in various fields, such as in designing electronic devices, calculating capacitance, and studying the behavior of electric fields in different materials. It also plays a crucial role in understanding the behavior of charged particles in electric fields.

Back
Top