- #1
johnq2k7
- 64
- 0
The base of a solid is the region bounded by y= 2*sqrt(sin(x)) and the x-axis, with x an element of [0, (pi/2)]. Find the volume of the solid, given that the cross sections perpendicular to the x-axis are squares.
Work Shown:
cross sections are squares:
therefore A(x) is not equal to Pi*r^2 rather l^2
therefore A(x)= [sqrt(sin(x)]^2
therefore integral of A(x)dx of x-values from 0 to Pi/2 should provide the answer
I think my approach is wrong and my integral for A(x) dx is wrong as well please help!
Work Shown:
cross sections are squares:
therefore A(x) is not equal to Pi*r^2 rather l^2
therefore A(x)= [sqrt(sin(x)]^2
therefore integral of A(x)dx of x-values from 0 to Pi/2 should provide the answer
I think my approach is wrong and my integral for A(x) dx is wrong as well please help!