- #1
reybob
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Homework Statement
The question asked is to make a bowl out of polynomial equations rotated around the y axis. The bottom of the bowl has to have a maximum at the center and a minimum at some distance from the center.
The equations I want to use are x^2+10, 1.3x^2 and -.7x^2 + 4.
The problem I face is what to do about the bottom of the bowl, since it is comprised of 2 functions meeting to form a minimum. Should I treat those two as its own volume of revolution, find the volume and then subtract the interior (top of bowl) from that total?
Homework Equations
Disc method: pi*integ: r(y)^2 dy
The Attempt at a Solution
pi*Integ: ((y-10)^1/2)^2 - [pi*Integ: ((y/1.3)^1/2)^2 - ((y-4/.7)^1/2)^2]
Is my attempt correct? The volume I am trying to find is bounded by x=0 (the y axis) and the 3 other equations