Volume of Revolution: Intuitive Explanation

In summary, the area between the f(x) graph and the x-axis from, say x=1 to infinity is infinite, but the volume of revolution of f(x) around the x-axis is finite. This paradoxical result is explained by the fact that when x is greater than 1, the power of x is greater than -1, and so the term 's' in the integral becomes infinite.
  • #1
Aeneas
27
0
If f(x) = x to a power between -0.5 and -1, the area between the f(x) graph and the x-axis from, say x=1 to infinity is infinite, but the volume of revolution of f(x) around the x-axis is finite. This seems counter-intuitive. Can anyone give a satisfying explanation of this - preferably a geometrical one please - not just the algebraic integration please - as I'm struggling with this idea.

Thanks, in anticipation.
 
Physics news on Phys.org
  • #2
What makes you say the volume is finite?
 
  • #3
for [tex]\frac{1}{x}[/tex] he's right volume is finite but surface area and integral are infinite

http://en.wikipedia.org/wiki/Gabriel's_Horn

down at the bottom there's a good explanation
 
  • #4
daveb - For -1 is less than the power of x is less than -0.5 (Sorry, I don't have any notation available) adding 1 to the power will; make that power positive, so the chosen point, say 's' above 1 will be in the numerator and the term will become infinite as 's' tends to infinity. When you square the function, though, to get the volume, the power of x will be doubled, making it less than -1, so when the result is integrated, the power of x will still be less than one, the 's' term will be in the denominator and so the term will tend to zero as 's' tends to infinity.Mnay thanks, daveb and ice109 for your replies.
 
  • #5
Aeneas said:
daveb - For -1 is less than the power of x is less than -0.5 (Sorry, I don't have any notation available) adding 1 to the power will; make that power positive, so the chosen point, say 's' above 1 will be in the numerator and the term will become infinite as 's' tends to infinity. When you square the function, though, to get the volume, the power of x will be doubled, making it less than -1, so when the result is integrated, the power of x will still be less than one, the 's' term will be in the denominator and so the term will tend to zero as 's' tends to infinity.Mnay thanks, daveb and ice109 for your replies.

click advanced reply and click the little sigma right right corner after the # and the PHP icon.
 
  • #6
Thanks for that tip ice109. The Gabriel's Horn explanation in Wikipedia in good, much better than Weisstein, who does not even try to tackle it, but it still does not really satisfy in terms of intuitive geometrical thinking. Also 1/x is only one of a family of functions for which this paradox occurs, which is not made clear. Is there a clue here? Thanks for that, anyway.
 
  • #7
infinite things are not spacially intuitive, by virtue of never knowing infinity you can not have intuition about it.
 
  • #8
Last edited by a moderator:

FAQ: Volume of Revolution: Intuitive Explanation

What is the volume of revolution?

The volume of revolution is the volume of a three dimensional object created by rotating a two dimensional shape around an axis.

How is the volume of revolution calculated?

The volume of revolution can be calculated using the formula V = π∫f(x)^2 dx, where f(x) is the function representing the shape being rotated and the integral is taken over the interval of the shape.

What are some real-world applications of the volume of revolution?

The volume of revolution is used in engineering, architecture, and design to calculate the volume of objects such as pipes, containers, and sculptures.

What is the difference between the volume of revolution and surface area of revolution?

The volume of revolution is the measure of the space inside the object, while the surface area of revolution is the measure of the outer surface of the object.

Are there any limitations to using the volume of revolution?

One limitation is that the formula only applies to objects with rotational symmetry around the axis. It also assumes that the object is solid and has a constant cross-sectional area.

Similar threads

Back
Top