- #1
qinglong.1397
- 108
- 1
Hi, everybody. I have some problem with Wald's statement shown in the picture. This is from the last paragraph in Page 178.
He claimed that there are only solutions with two of the [itex]p_{\alpha}[/itex] positive and one negative. But it's easy to find out that if two of the [itex]p_{\alpha}[/itex] are negative while the third positive, there is no contradiction.
Can you guys help me with this? Why should all the solutions have two positive [itex]p_{\alpha}[/itex] and one negative? Thank you
(The picture is from http://books.google.com/books?id=9S...ce=gbs_ge_summary_r&cad=0#v=onepage&q&f=false)
He claimed that there are only solutions with two of the [itex]p_{\alpha}[/itex] positive and one negative. But it's easy to find out that if two of the [itex]p_{\alpha}[/itex] are negative while the third positive, there is no contradiction.
Can you guys help me with this? Why should all the solutions have two positive [itex]p_{\alpha}[/itex] and one negative? Thank you
(The picture is from http://books.google.com/books?id=9S...ce=gbs_ge_summary_r&cad=0#v=onepage&q&f=false)