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Todee
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Homework Statement
Consider a 50 mH inductor .
find i at t=10 ms if v= 20t^2 V for t>-0.1 ms and i(-0.02)=5 mA.
Todee said:Homework Statement
Consider a 50 mH inductor .
find i at t=10 ms if v= 20t^2 V for t>-0.1 ms and i(-0.02)=5 mA.
Todee said:Homework Statement
Consider a 50 mH inductor .
find i at t=10 ms if v= 20t^2 V for t>-0.1 ms and i(-0.02)=5 mA.
Todee said:I think that I should use this equation
i(t)= 1/L ∫ V(t)dt + i(t)→(intial current )
... the problem tell me i(-0.02)=5 mA , i think it's -0.02 ms !...
the final answer is 6.2 mA but i couldn't get it :(
The current in an inductor can be calculated using the formula I = V/R, where I is the current, V is the voltage, and R is the resistance.
The unit of measurement for inductance is the henry (H).
The current in an inductor changes over time based on the rate of change of the magnetic field within the inductor. As the magnetic field changes, it induces a voltage in the inductor, which then affects the current.
Yes, the current in an inductor can be negative. This occurs when the voltage across the inductor is changing rapidly, causing the current to flow in the opposite direction.
In a DC circuit, the current in an inductor initially rises as the magnetic field builds up, but eventually reaches a steady state where the current is constant. This is known as the steady-state current.