- #36
RandallB
- 1,550
- 0
?curt said:RandallB,
You said “Ther could arrive at the same time if they start at different time could they.” I don’t understand this sentence. Can you elaborate?
You said “the entire problem is based on two simultaneously lightning strikes at A & B while A' is at A and B' is at B.” Where did Einstein mention A’ and B’? If A’ is at A and B’ is at B, are you implying that the train is the same length as the distance from A to B? If so, why? What relevance does this have?
If you say at A’ is at A and B’ is at B, then the answer to your question “What is the distance for A’ & B’ ?” in post #20, is A’ = -B’, where A’ – B’ = 10 light seconds of distance. If I have this wrong, please explain.
If A’ – B’ = 10 light seconds = A – B, then Strike time’ for A’ = Strike time’ for B’. If I have this wrong, please explain.
How do you expect Einsein to go back in time and change his text to suit our modern use of (') as in M' to indicate TRAIN and our not using the mark (') as in M to indicate EMBANKMENT ?
Einstein was only addressing the time of the two events as measured from two different referance frames. You will find this easier to understand if you also define where in each referance frame the event happened!
With distance defined from M to B as 10 units of length (M to A would be -10 units) -- How do you get distance measured by M' to B' as 10 as well?? It is simply not trure the distace between strikes in M' frame (A' to B') is 25 units of distance (speed 0.6c).
Do the math on time as well and you will see that B' saw its nearby strike well BEFORE A' saw its nearby strike.
Since they are both the same distance from M' of course M' will see the strike from B' first - - IT HAPPENED FIRST.
That is the only point Einstein was making - simultaneous events in the M frame (embankment frame) are not simultaneous in the M' frame (train frame).