Was the Car Speeding Based on Skid Mark Analysis?

In summary: Instead, help the OP with the concepts, and let them do their own homework.In summary, a car with a mass of 1000kg skidded to a stop leaving tire tracks of 32 meters. The coefficient of sliding friction between the tires and the road is 0.45. By using the formula F_f = u_kmg and kinematics equations, it can be determined that the car's deceleration was 4.41 m/s^2. Using the kinematics equation v_f^2 = v_i^2 + 2a_fx, it can be determined that the car's initial velocity was around 17 m/s. Therefore, the driver was exceeding the speed limit of 11.3
  • #1
Elo21
7
0

Homework Statement



you are a crime scene specialists. a car in an accident had skidded to a stop and left tire tracks for 32 meters. The coefficient of sliding friction between the tires and road is .45, and the car's mass is 1000kg. Was the driver exceeding 25mph (11.3m/s) speed limit?


Homework Equations



u= Force Friction / Normal Force
F net= m*a

I can't figure it out because i don't think i know all the formulas i need to know.

The Attempt at a Solution



I tried but it is to much to write.
 
Physics news on Phys.org
  • #2
Welcome to pf.

You know the friction force acting to slow the car.
So you can either use F=ma to work out the acceleration and what initial speed it would need to take that distance to stop.
Or you know energy= force * distance, work out how much energy you lost to friction over that distance and what initial kinetic energy (and so speed) you must have had.
 
  • #3
Elo21 said:

Homework Statement



you are a crime scene specialists. a car in an accident had skidded to a stop and left tire tracks for 32 meters. The coefficient of sliding friction between the tires and road is .45, and the car's mass is 1000kg. Was the driver exceeding 25mph (11.3m/s) speed limit?


Homework Equations



u= Force Friction / Normal Force
F net= m*a

I can't figure it out because i don't think i know all the formulas i need to know.

The Attempt at a Solution



I tried but it is to much to write.

The first objective is to determine the car's deceleration. After that, we use kinematics to calculate the car's initial velocity and compare it to the speed limit.

The frictional force acting against the car's motion can be written as:

[tex]F_f = u_kF_N[/tex]

The normal force is mg, so the equation becomes:

[tex]F_f = u_kmg[/tex]

We can reduce this equation to:

[tex]ma_f = u_kmg[/tex]

where, after canceling the masses from both sides, we have:

[tex]a_f = u_kg[/tex]

so

[tex]a_f = - 4.41 m/s^2[/tex]

Now plug this into the kinematics equation:

[tex]v_f^2 = v_i^2 + 2a_fx[/tex]

Final velocity is 0. Just solve for the initial velocity and you should get around 17 m/s. The driver was speeding.
 
  • #4
thank you.
 
  • #5
Cryxic said:
The first objective is to determine the car's deceleration. After that, we use kinematics to calculate the car's initial velocity and compare it to the speed limit.

The frictional force acting against the car's motion can be written as:

[tex]F_f = u_kF_N[/tex]

The normal force is mg, so the equation becomes:

[tex]F_f = u_kmg[/tex]

We can reduce this equation to:

[tex]ma_f = u_kmg[/tex]

where, after canceling the masses from both sides, we have:

[tex]a_f = u_kg[/tex]

so

[tex]a_f = - 4.41 m/s^2[/tex]

Now plug this into the kinematics equation:

[tex]v_f^2 = v_i^2 + 2a_fx[/tex]

Final velocity is 0. Just solve for the initial velocity and you should get around 17 m/s. The driver was speeding.

Please do not do the OP's homework for them. That's not how the Homework Help forums work here at the PF.
 

FAQ: Was the Car Speeding Based on Skid Mark Analysis?

What is the difference between scalar and vector quantities?

Scalar quantities are physical quantities that have only magnitude, such as mass, temperature, and time. Vector quantities, on the other hand, have both magnitude and direction, such as velocity, acceleration, and force.

How do I calculate the acceleration of an object?

Acceleration is calculated by dividing the change in velocity by the change in time. The formula for acceleration is a = (vf - vi)/t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

What is the difference between distance and displacement?

Distance is the length of the path traveled by an object, while displacement is the shortest distance between the initial and final positions of an object. Distance is a scalar quantity, while displacement is a vector quantity.

How does Newton's First Law of Motion apply to real-life situations?

Newton's First Law of Motion states that an object at rest will remain at rest, and an object in motion will remain in motion at a constant velocity, unless acted upon by an external force. This law applies to real-life situations, such as a book staying on a table until someone picks it up or a car continuing to move forward until the brakes are applied.

What is the difference between kinetic and potential energy?

Kinetic energy is the energy an object possesses due to its motion, while potential energy is the energy an object possesses due to its position or state. Kinetic energy can be calculated using the formula KE = 1/2mv^2, where m is mass and v is velocity. Potential energy can be calculated using the formula PE = mgh, where m is mass, g is the acceleration due to gravity, and h is the height of the object.

Similar threads

Back
Top