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rkum99
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Homework Statement
Suppose you adjust your garden hose nozzle for a hard stream of water. You point the nozzle
vertically upward at a height of 1.5m above the ground. When you quickly move the nozzle away
from the vertical, you hear the water striking the ground next to you for another 2.0s. What is
the water speed as it leaves the nozzle?
Homework Equations
Δx =Vo t + 1/2 at^2
The Attempt at a Solution
Δx =Vo t + 1/2 at^2
-1.5m = (2s) Vo + (1/2) (-9.8 m/s^2) (2s)^2
-1.5m = (2s) Vo - 19.6 m
Vo = 9.05 m/s
Now the above solution seems to be correct, but I am not sure why t should = 2s.
I ended plugging 2 sec. in without really thinking about it, but now I am not able to
spatially visualize what is going on with the water.
Any help appreciated.