- #1
ShizukaSm
- 85
- 0
Homework Statement
The Attempt at a Solution
Let's divide it in three states.
[itex]E_1(\text{Initial state}) \\P = 3.5 \text{MPa} \\T = T_\text{sat@P} + 5 = 242.56 + 5 = 247.56\text{ C} \\ h_v = \text{Known value (table)}\\ v_v = \text{Known value (table)}[/itex]
[itex]E_2(\text{When the piston hit the stops.}) \\P = P_\text{@ state 1} = 3.5 \text{MPa}(\text{Because the piston is still providing pressure}) \\T = 242.56\text{ C} \\ h_f = \text{Known value (table)}\\ v_f = \text{Known value (table)}\\ x = 0[/itex]
[itex]E_3(\text{Final state}) \\P = ?? \\T = 200 \text{ C} [/itex]
That were as far as I could get, which allowed me to solve a and b. I can't understand however, how to go from state 2 to state 3. The book solution affirms that specific volume is constant(s2>s3), and as such I should use it to calculate the final value of specific volume and find the data in "Saturated water" table.
I don't understand why, though. Apparently the water became steam again? How could I determine that? What is there preventing the water from simply cooling in a compressed liquid state and decreasing its specific volume?