- #1
Petyab
- 20
- 0
Useful equation.
Avg. Power
p(t)=(V^2(t))/R
My attempt at instantaneous power was
p(t,V,R)= ∫(0->1 for t ∫0->5 for V and ∫0->.1 for R V^2(t)/RdvdRdt
Integrating I go the triple integral of V^3t^2/6R^2
Substituting my values in gave a wattage of 1,250 watts/m^2 at t=1 second, v=5 volts, and R=1 ohms
Using Ohms Law V=IR or I=V/R I calculate now as I write this a current of
I=5/.1=50 amps
Is this correct?
Avg. Power
p(t)=(V^2(t))/R
My attempt at instantaneous power was
p(t,V,R)= ∫(0->1 for t ∫0->5 for V and ∫0->.1 for R V^2(t)/RdvdRdt
Integrating I go the triple integral of V^3t^2/6R^2
Substituting my values in gave a wattage of 1,250 watts/m^2 at t=1 second, v=5 volts, and R=1 ohms
Using Ohms Law V=IR or I=V/R I calculate now as I write this a current of
I=5/.1=50 amps
Is this correct?