Wave Interference with 2 speakers

In summary, the problem involves two speakers located 4.0m apart and a listener seated 25.0m from one speaker and 27.0m from the other. The speakers are driven at a frequency that is swept from 100 to 500 Hz. The goal is to find the frequencies at which the waves constructively or destructively interfere when the speakers are in phase. By converting the equations from functions of wavelength to frequency, the solution involves finding all the frequencies between 100 and 500 Hz that satisfy the equations.
  • #1
exzacklyright
12
0

Homework Statement


Two speakers located 4.0 m apart. Listener is seated 25.0m from 1 speaker, and 27.0m from the other. We drive the two speakers at a freq. which we sweep from 100 to 500 Hz. If the 2 speakers are in phase, find the frequencies at which the waves constructively/destructively interfere.

Speed of sound = 343 m/s

Homework Equations



x2-x1 = n[itex]\lambda[/itex] (constructive)

x2-x1 = (n+0.5)[itex]\lambda[/itex] (destructive)

lamda = v/f

The Attempt at a Solution



Not sure to be honest where to start since there is a range of frequencies.
 
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  • #2
exzacklyright said:

Homework Statement


Two speakers located 4.0 m apart. Listener is seated 25.0m from 1 speaker, and 27.0m from the other. We drive the two speakers at a freq. which we sweep from 100 to 500 Hz. If the 2 speakers are in phase, find the frequencies at which the waves constructively/destructively interfere.

Speed of sound = 343 m/s

Homework Equations



x2-x1 = n[itex]\lambda[/itex] (constructive)

x2-x1 = (n+0.5)[itex]\lambda[/itex] (destructive)

lamda = v/f

The Attempt at a Solution



Not sure to be honest where to start since there is a range of frequencies.
Well the first thing to do is convert your two equations from functions of wavelength to frequency.

After you've done that, you just need to find all the frequencies between the two limits that satisfy those equations.
 
  • #3
Hootenanny said:
Well the first thing to do is convert your two equations from functions of wavelength to frequency.

After you've done that, you just need to find all the frequencies between the two limits that satisfy those equations.

yeah I figured it out. thx.
 

FAQ: Wave Interference with 2 speakers

What is wave interference with 2 speakers?

Wave interference with 2 speakers is a phenomenon that occurs when two sound waves from different sources intersect and overlap. This results in a combined wave that can either amplify or cancel out the original waves.

How does wave interference with 2 speakers work?

When two sound waves meet, they combine through a process called superposition. This means that the displacements of the two waves are added together to create a new wave. Depending on the phase and amplitude of the waves, the resulting wave can be either constructive (amplified) or destructive (canceled out).

What is the difference between constructive and destructive interference?

Constructive interference occurs when two waves are in phase and overlap, resulting in an amplified wave. Destructive interference occurs when two waves are out of phase and overlap, resulting in a canceled out wave.

How can wave interference with 2 speakers be observed?

Wave interference with 2 speakers can be observed by setting up two speakers close to each other and playing the same frequency at the same volume. Move around the room and you will notice areas where the sound is louder (constructive interference) and areas where it is quieter (destructive interference).

What applications does wave interference with 2 speakers have?

Wave interference with 2 speakers has various applications, including noise cancellation technology, audio engineering, and acoustic levitation. It is also used in music production to create unique sound effects and in architecture to design acoustically sound spaces.

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