Webpage title: Solving for Tension in a Rope Problem

In summary, a mountain climber is hanging between two cliffs by a rope. The tension in the left and right sides of the rope are not the same. The mountain climber weighs 565 N, which is the equivalent of the normal force (Fn) that is pulling her up to keep her from falling. The normal force is right, which would act straight up, but is there anything holding her straight up? The tension on the rope is the only thing that I can think of.
  • #36
so T1, 80*, =3253.7N

T2, 65*, =1336.9N

does this look right, seems like quite a bit of tension
 
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  • #37
i tried those answers but they were incorrect.
 
  • #38
no- I think we did something wrong. T1+T2=565N so you could say

T1=565-T2
 
  • #39
ok, then how do i find T1 or T2
 
  • #40
I messed you up more then I helped, sorry man. I need my notes/book/calculator and they are all in my car.. sorry to take you down the wrong track like that
 
  • #41
ok, if both lengths of rope were equal

T1=Fg/2

T2=Fg/2

they are not but this gives me an idea...
 
  • #42
ok...
 
  • #43
There are three forces acting on the person:
- Tension (T1) from left rope (acting at the angle of the rope)
- Tension (T2) from right rope (acting at the angle of the rope)
- Weight (W) acting down (which is given)

Since she's in equilibrium:
- The sum of the vertical force components must equal 0
- The sum of the horizontal force components must equal 0

That will give you two equations, which you can solve to find the two unknowns: T1 & T2.
 

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