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enryiggins
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I am trying to teach myself AS maths. This is from Introducing mechanics a txt book by Jefferson and Beadsworth. exercise 2C question 1 part vi)
Question given vector b=6i-3j-2k;
|b| is established as = 7 by calculation
Question
Calculate the angles between b and positive x-, y- and z- directions.
My answer: these are
sine alpha =6/7 = 59 degrees - subtract from 180 to give angle from z axis
Sine beta =2/7 = 16.6 degrees - this is angle from x axis
Sine theta = 3/7 = 25.4 degrees. Need to add 90 degrees to give angle from y axis.
However these are not the correct answers. The correct answers appear to be cosines of the above. This does not make sense to me can you expalin?
Question given vector b=6i-3j-2k;
|b| is established as = 7 by calculation
Question
Calculate the angles between b and positive x-, y- and z- directions.
My answer: these are
sine alpha =6/7 = 59 degrees - subtract from 180 to give angle from z axis
Sine beta =2/7 = 16.6 degrees - this is angle from x axis
Sine theta = 3/7 = 25.4 degrees. Need to add 90 degrees to give angle from y axis.
However these are not the correct answers. The correct answers appear to be cosines of the above. This does not make sense to me can you expalin?