- #1
EhsanZ
- 11
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In equation below
〖H₁〗^2/〖H₀〗^2 =Ω₀(cri) (R₀⁴)/(R₁⁴(1+z(eq)))
Why is the term “(1+z(eq))” negligible in denominator according to the term “ R₁⁴ ” ?
Weinburg did it in his book named "Cosmology".
〖H₁〗^2/〖H₀〗^2 =Ω₀(cri) (R₀⁴)/(R₁⁴(1+z(eq)))
Why is the term “(1+z(eq))” negligible in denominator according to the term “ R₁⁴ ” ?
Weinburg did it in his book named "Cosmology".