Weird question in "Vectors" chapter

In summary, the problem involves two aircraft approaching an aircraft carrier at different distances and angles. The coordinates are given in a 3-dimensional system with the x-axis pointing east, the y-axis pointing north, and the z-axis in the vertical direction. The distance between the two aircraft can be found using the distance formula with 3 variables. It is important to carefully read and understand the problem and use the given information and hints to find the correct solution.
  • #1
Rijad Hadzic
321
20

Homework Statement


Two aircraft approaching an aircraft carrier are detected by radar. The first aircraft is at a horizontal distance of 34.3 km in the direction 42 deg north of east. and has altitude 2.4 km

The second aircraft, at altitude 1.2 km, is at horizontal distance of 42.6 km in the direction 37 deg north of east.

What is the distance separating the two aircraft? Hint: use a coordinate system with the x-axis pointing east, the y-axis pointing north, and the z axis in the vertical direction

Homework Equations

The Attempt at a Solution


Ok I really don't understand the hint. it says the z axis in the vertical direction, correct me if I'm wrong but isn't north the vertical direction, which they said make the y axis?

And why do you even need an axis for this problem? Same with the angles.

I used the distance forumla: [itex] ((x_2 - x_1)^2 + (y_2 - y_1)^2 )^{1/2} [/itex]

plugging 42.6 as x_2 and 34.3 as x_1, 1.2 for y_2 and 2.4 for y_1

and got answer 8.38 km.

Book says answer is 9.02 km.

My doubts here are: first off, why would I need to use a 3 dimensional axis?

Second off, I used arc tan to check the angles and they seem off.

For example, on aircraft 1 I did arctan(2.4/34.3) and got 4 degrees, not even close to their stated 42 degrees.

Anyone have any clue? My book is starting to piss me off cause if you've been following the last two questions I asked on here apparently my book was wrong as well, I really want to complain to the author and I question why this was used in an introductory physics course cause I don't feel like I'm learning the material right because of all the contradictions.

Sorry for venting just had to get that off of my chest, and if i am indeed wrong I'm just going to look dumb for complaining lol.

Anyways can anyone please help me.
 
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  • #2
Say then, you use the x and y coordinates in the horizontal plane to describe the displacements (from the origin).
How can you describe the altitude without using a z (vertical axis)?
 
  • #3
J Hann said:
Say then, you use the x and y coordinates in the horizontal plane to describe the displacements (from the origin).
How can you describe the altitude without using a z (vertical axis)?

Wouldn't horizontal distance be on the x-axis and altitude be vertical distance?
 
  • #4
Rijad Hadzic said:
first off, why would I need to use a 3 dimensional axis?
Because you've been given the locations in 3 dimensions.
Rijad Hadzic said:
correct me if I'm wrong but isn't north the vertical direction, which they said make the y axis?
Imagine yourself standing on the ground facing north. So, y-axis is going straight ahead (along north), x-axis is going to your right (east) and z axis is going towards the sky (vertically upward).
 
  • #5
cnh1995 said:
Because you've been given the locations in 3 dimensions.

Imagine yourself standing on the ground facing north. So, y-axis is going straight ahead (along north), x-axis is going to your right (east) and z axis is going towards the sky (vertically upward).
alright I think I'm starting to get it. I'm going to work it again and come back if I need any help..
 
  • #6
Looks like I'm going to have to use the distance formula with 3 variables..
 
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  • #7
Got the correct answer guys.

Main thing I learned this problem:

I have a one track thought, I need to try harder to dig for the answer. They even gave me a hint yet I still thought that my way was right. I need to stop looking for help and basically try to understand the question better on my own.
 
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FAQ: Weird question in "Vectors" chapter

What are vectors and how are they used in science?

Vectors are quantities that have both magnitude (size) and direction. They are used in science to represent physical quantities such as velocity, force, and displacement. They are also used in mathematical models to describe and predict the behavior of physical systems.

Why are vectors important in physics?

Vectors are important in physics because they can accurately describe and predict the motion and behavior of objects in the physical world. By using vectors, scientists can represent complex physical quantities and analyze their effects on a system.

What are the different types of vectors?

There are two types of vectors: scalar and vector. Scalar quantities have only magnitude, while vector quantities have both magnitude and direction. Examples of scalar quantities include temperature and mass, while examples of vector quantities include velocity and displacement.

How do you add and subtract vectors?

To add or subtract vectors, you must first break them down into their components (x and y or i and j). Then, add or subtract the components separately to get the resulting vector. You can also use graphical methods or trigonometry to add or subtract vectors.

How are vectors used in real-world applications?

Vectors are used in many real-world applications, such as navigation systems, weather forecasting, and computer graphics. They are also used in fields like engineering and physics to model and analyze the behavior of physical systems. In everyday life, vectors are used to represent and calculate quantities like velocity and force.

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