- #1
paweld
- 255
- 0
I found the formula for the number of independent components of
Weyl tensor in n-dimensional manifold:
[tex]
(N+1)N/2 - \binom{n}{4} - n(n+1)/2~~~~~N=(n-1)n/2
[/tex]
This expression implies that in 3 dimension Weyl tensor has 0 independent
components, so it's 0. Does it implies that any three-dimensional manifold
is conformally flat (maybe the formula I've written above is incorrect for n<4)?
Weyl tensor in n-dimensional manifold:
[tex]
(N+1)N/2 - \binom{n}{4} - n(n+1)/2~~~~~N=(n-1)n/2
[/tex]
This expression implies that in 3 dimension Weyl tensor has 0 independent
components, so it's 0. Does it implies that any three-dimensional manifold
is conformally flat (maybe the formula I've written above is incorrect for n<4)?