- #1
Ritzycat
- 171
- 4
Homework Statement
A hunter aims directly at a target (on the same level) 38.0m away. (a) If the arrow leaves the bow at a speed of 23.1m/s, by how much will it miss the target? (b) At what angle should the bow be aimed so the target will be hit?
Notes: Initial Y velocity is 0m/s. Vi = Vix
Homework Equations
Kinematic equations
The Attempt at a Solution
I was able to solve the first part (a), fairly straightforward.
38m = 23.1m/s * t
t = 1.65s
Yf = 1/2(-9.8m/s^2)(1.65s^2) = -13.3m, target missed by 13.3 meters.
I am mostly having difficulties with the second part. The answer says it is 22.1 degrees, but I don't know how to get to that answer.
I tried setting up a triangle of the final velocities and see what that angle would be.
Final velocity X: 23.1 m/s
Final velocity Y: (-9.8m/s^2)(1.65s) = 16.17m/s
Final velocity overall: 28.2m/s
tan^-1(x) = 16.17/23.1 = 35 degrees.
How should I get to the correct angle of 22.1 degrees?