What are the considerations when finding vector equations for lines and planes?

In summary: To determine a unique plane, you need a point and a vector perpendicular to the plane, which we call the normal vector. To find the normal vector, you can use the cross product of the given vector and any other vector on the plane. This will give you a vector perpendicular to both of these vectors, which is the normal vector. In summary, when finding vector equations for lines, if given a vector and a line parallel to it, and a vector and a line perpendicular to it, you will need to use the cross product to find the normal vector. For planes, a normal vector is a vector perpendicular to the plane that can be used to determine a unique plane when given a point on the plane.
  • #1
suspenc3
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A few Questions:

a)when finding vector equations (for lines), what do you different when they give you a vector and a line parallel to this vector, and a vector and a line perpendicular to the vector.

b)concerning planes, can someone briefly explain the normal vector.

Thanks.
 
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  • #2
suspenc3 said:
A few Questions:

a)when finding vector equations (for lines), what do you different when they give you a vector and a line parallel to this vector, and a vector and a line perpendicular to the vector.

b)concerning planes, can someone briefly explain the normal vector.

Thanks.

I'll try to help with b).

The easiest way to copletely determine a plane is with one point T1 = (x1, y1, z1) (belonging to the plane) and a vector n which is perpendicular to the plane, which we call the normal vector. Now, let T = (x, y, z) be any point in the plane. Obviously, n must be perpendicular to the vector [tex]\vec{T_{1}T}[/tex], which implies n(r-r1)=0 ...(1), where r1 is the radius vector determined by the point T1, and r the radius vector determined by the point T. Further on, (1) directly implies A(x-x1) + B(y-y1)+ C(z-z1) = 0, where n=Ai+Bj+Ck. This is a general equation of a plane.
 
  • #3
Yeah that explains it, so say they give you a point and a vector parallel to the plane, how would you get the Normal? Would you just cross the vector and the point?
 
  • #4
suspenc3 said:
Yeah that explains it, so say they give you a point and a vector parallel to the plane, how would you get the Normal? Would you just cross the vector and the point?

A point and a vector parallel to a plane do not determine a plane. They determine an infinite number of planes.
 

FAQ: What are the considerations when finding vector equations for lines and planes?

What is the equation of a line?

The equation of a line is written in the form y = mx + b, where m represents the slope of the line and b represents the y-intercept. This equation can also be written as Ax + By = C, where A, B, and C are constants.

How do you find the slope of a line?

The slope of a line can be found by using the formula m = (y2 - y1)/(x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. Alternatively, if the equation of the line is in the form y = mx + b, the slope is equal to the coefficient of x, or m.

What is the equation of a plane?

The equation of a plane in three-dimensional space is written in the form Ax + By + Cz = D, where A, B, C, and D are constants. This equation represents all the points (x, y, z) that lie on the plane.

How do you find the equation of a plane?

To find the equation of a plane, you need to have at least three non-collinear points on the plane. Using these points, you can set up a system of equations and solve for the constants A, B, C, and D in the equation Ax + By + Cz = D. There are also other methods, such as using a normal vector and a point on the plane, to find the equation.

What is the relationship between lines and planes?

A line can intersect a plane in three different ways: it can be parallel to the plane, it can intersect the plane at a single point, or it can intersect the plane at infinitely many points. The equation of a line can also be used to determine if it lies on a given plane by plugging in the coordinates of any point on the line into the plane's equation. If the resulting equation is true, the line lies on the plane.

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