What Are the Cosets in Q/Z(Q)?

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The discussion revolves around finding the cosets in the group Q/Z(Q), where Q refers to the quaternion group. It is established that Z(Q), the center of Q, is normal in Q. Participants express confusion about identifying cosets without specific elements from Q or Z(Q) and clarify that Q is indeed the quaternion group, not the rationals. The center is determined to include elements that commute with all others, leading to representatives for each coset being identified. The conclusion confirms that the identified cosets are correct, emphasizing the importance of understanding the group's structure.
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Homework Statement


Find the cosets in Q/Z(Q)


Homework Equations





The Attempt at a Solution



So Z(Q) is the centre of Q..
Then Z(Q) is normal in Q.

I don't get what the cosets would be without any given elements of Q or Z(Q)..
But I'm assuming since it is the centre of Q there is some trick?

Thanks.
 
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What is Q here? The quaternion group? I will assume it is.

What is the center of Q? Does i commute with every element? does j? does k? does -1? etc.? Once you have determined the center you should be able to find representatives for every coset in Q/Z(Q).
 
Hmm, is the operation simply addition? If so, Q is commutative, and Z(Q)=Q.
 
I get:
{1,-1} = Z(Q)= Z(Q)(-1)
{i, -i} = Z(Q)i = Z(Q)(-i)
{j, -j} = Z(Q)j = Z(Q)(-j)
{k, -k} = Z(Q)k = Z(Q)(-k)

is this correct?
 
Yes, this is correct. Sorry for the first answer, I thought Q ment rationals...
 
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