What Are the Dimensions of A, B, and D in the Rocket Velocity Equation?

In summary, the conversation discusses the dimensions of physical quantities A, B, and D in relation to the velocity of a rocket in space. The equation V = A + B log(D/m) is given and it is determined that A has dimensions of L/T and B has dimensions of L/T as well. The dimensions of D are still being determined, but it is suggested that log has no dimensions and D may have dimensions of mass (M).
  • #1
BioCore

Homework Statement



Consider a Rocket in space, far removed from external gravitational influences, and suppose the engine starts up. As long as the engines are running, its instantaneous velocity v is a function of its mass. V is given by:

V = A + B log(D/m)

A, B, D are physical quantities, find the dimensions of A, B and D.

Homework Equations



V = A + B log(D/m)

The Attempt at a Solution



From here I will refer to dimensions as such: [], ex. [V] dimensions of velocity.

[V] = L/T
thus [A] = L/T

I need to still find the and [D]. I am not entirely sure here of how to approach. But would the dimensions of log be nothing, in other words [D] = M or mass.

and thus = L/T as well. Or it this a stupid assumption to make?

Thank you for the help.
 
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  • #2
Makes sense to me.
 
  • #3


I would approach this problem by first identifying the units of each term in the equation. The left side of the equation, V, represents velocity and has units of length per time ([V] = L/T). The first term on the right side, A, also represents velocity and has the same units as V ([A] = L/T).

Now, let's look at the second term, B log(D/m). The log function is dimensionless, so we can ignore it for now. The remaining terms, B and D/m, must have the same units in order for the equation to be dimensionally consistent.

Let's start with B. We know that must have units of length per time, so let's look at the units of D/m. D has units of length ([D] = L) and m has units of mass ([m] = M). So, D/m must have units of length per mass ([D/m] = L/M). Therefore, must also have units of length per mass ( = L/M).

Now, let's look at D. We know that [D] = L, but we also know that D represents a physical quantity. In this case, it represents a distance (such as the diameter of the rocket). Therefore, we can say that [D] = L (length) or [D] = [L] (distance).

In summary, the dimensions of A, B, and D are:
[A] = L/T (length per time)
= L/M (length per mass)
[D] = L or [D] = [L] (length or distance)

Note that the dimensions of D can be written as simply L, since distance is a fundamental dimension and does not require a unit.

I hope this helps! Keep up the good work in your studies.
 

FAQ: What Are the Dimensions of A, B, and D in the Rocket Velocity Equation?

What are the three constants in the dimensions formula?

The three constants in the dimensions formula are length, mass, and time. These three quantities are used to measure physical quantities in our universe.

Why are dimensions important in scientific research?

Dimensions are important in scientific research because they provide a standardized way to measure and compare physical quantities. This allows scientists to make accurate and consistent calculations and predictions.

How do dimensions impact our understanding of the physical world?

Dimensions help us understand the physical world by providing a framework for understanding and describing the fundamental units of measurement. They also allow us to make connections between seemingly unrelated quantities and phenomena.

What happens if dimensions are not consistent in a scientific equation?

If dimensions are not consistent in a scientific equation, it means that the equation is mathematically incorrect. In order for an equation to be valid, the dimensions on both sides of the equation must be the same.

Can dimensions change or vary in different contexts?

Dimensions themselves do not change, but the units used to measure them can vary in different contexts. For example, length can be measured in meters, feet, or inches depending on the context. However, the fundamental dimensions of length remain the same.

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