What Are the Dynamics of a Single Species Population Model?

In summary, mathematical biology is a field that uses mathematical tools and models to study biological systems and processes. It has various applications, such as studying population dynamics and disease spread, and contributes to biology by providing a quantitative and predictive approach to understanding complex processes. To work in this field, one needs a strong foundation in mathematics, biology, and computer programming. Current research topics in mathematical biology include infectious diseases, cancer growth and treatment, biological pattern formation, and ecology and evolution.
  • #1
ra_forever8
129
0
Consider the single species population model defined by
dR/dt = [gR/(R+R_m)] - dR, t>0,
where g,R_m and d are all positive parameters and R(0) =R_0

(a) Describe the biological meaning of each term in the equation.

(b) Determine the steady-states of the system and discuss any constraints on the model parameters for the model to admit biologically meaningful solutions.

(c) Determine the steady-state stability and discuss any variation in this with respect to the model parameter values.

=>
a) gR represents the exponential growth of population
dR represents the exponential decay of population
g is the growth rate
d is the decay rate
what does R and R_m represent?
how can I define this term gR/(R+R_m)?
what is (R+R_m)? does it affect the gR for the grow?

b)
In single steady -state system, dR/dt =0
[gR/(R+R_m)] - dR =0
gR -dR(R+R_m) =0
R[g -d(R+R_m)] =0
either R=0
OR g -d(R+R_m)= 0
g- dR_m =0 (R=0)
R_m = g/d
R* = g/d (R_m = R*)
SO we have : (R*1, R*2) =(0, g/d)
is my R*1, R*2 correct. I am concern about R*2 because not sure about if I am allow to do _m = R*.
I am not sure constraint on the model parameters to admit biologically meaning solutions?

c)
to determine steady-state stability
let f(R) = [gR/(R+R_m)] - dR
df/dR = g ln(R+R_m) -d .
My differentiation may be wrong and don't know the term R_m while differentiating with respect to R.
I really don't know after that. and I know my answer is still incomplete.
please help me.
 
Mathematics news on Phys.org
  • #2
grandy said:
Consider the single species population model defined by
dR/dt = [gR/(R+R_m)] - dR, t>0,
where g,R_m and d are all positive parameters and R(0) =R_0

(a) Describe the biological meaning of each term in the equation.

(b) Determine the steady-states of the system and discuss any constraints on the model parameters for the model to admit biologically meaningful solutions.

(c) Determine the steady-state stability and discuss any variation in this with respect to the model parameter values.

=>
a) gR represents the exponential growth of population
dR represents the exponential decay of population
g is the growth rate
d is the decay rate
what does R and R_m represent?
how can I define this term gR/(R+R_m)?
what is (R+R_m)? does it affect the gR for the grow?

I would agree that the term $-dR$ represents an exponential decay. However,
the $\displaystyle \frac{gR}{R+R_m}$ is not exponential growth - exponential growth would look like a plain $gR$. It might be helpful to rewrite this term:
$$\frac{gR}{R+R_m}=g \frac{R}{R+R_m}=g \left[ \frac{R+R_m-R_m}{R+R_m}\right]
=g \left[ 1- \frac{R_m}{R+R_m}\right]=g- \frac{gR_m}{R+R_m}.$$
So your DE would then be
$$ \frac{dR}{dt}=g-dR- \frac{gR_m}{R+R_m}.$$

So, in looking at this, I would agree that $g$ is a growth term; however, it's not an exponential growth term, but linear. This could be a steady influx of population from outside, at a constant rate. The $-gR_m / (R+R_m)$ term represents something that always negatively affects the population, but is worse when the population is smaller, and not so bad when the population is larger. I don't know what this could correspond to. If I think of the pilgrims coming over to the US, then this term could be something like division of labor. When you have a very small population, there is a "critical mass" of people you need in order to sustain growth. This could be one way to think of this weird fraction. $R_m$ is some parameter associated with the "division of labor term". $d$, I would agree, represents a death rate, and this one is exponential, because it's multiplied by $R$. So the more population you have, the worse this term gets.

b)
In single steady -state system, dR/dt =0

Correct.

[gR/(R+R_m)] - dR =0
gR -dR(R+R_m) =0
R[g -d(R+R_m)] =0
either R=0
OR g -d(R+R_m)= 0

Good.

g- dR_m =0 (R=0)

This move is not valid. You said before that EITHER $R=0$ OR $g-d(R+R_m)=0$. You can't suddenly that to BOTH of them are zero simultaneously. Try this:
\begin{align*}
g-d(R+R_m)&=0 \\
g&=d(R+R_m) \\
\frac{g}{d} &=R+R_m \\
\frac{g}{d}-R_m&=R.
\end{align*}
So your other steady-state solution is $g/d-R_m$.

R_m = g/d
R* = g/d (R_m = R*)
SO we have : (R*1, R*2) =(0, g/d)
is my R*1, R*2 correct. I am concern about R*2 because not sure about if I am allow to do _m = R*.
I am not sure constraint on the model parameters to admit biologically meaning solutions?

I am not savvy enough to answer this question, either.

c)
to determine steady-state stability
let f(R) = [gR/(R+R_m)] - dR
df/dR = g ln(R+R_m) -d .
My differentiation may be wrong

It is. You "integrated" one term, and differentiated the other! Differentiating with respect to $R$ is fine - you'll get a "feel" for $d^2R/dt^2$ that way. I get:
\begin{align*}
\frac{d}{dR} \left[ g-dR- \frac{gR_m}{R+R_m}\right]&=
-d-g R_m \frac{d}{dR}(R+R_m)^{-1} \\
&=-d+\frac{gR_m}{(R+R_m)^2}.
\end{align*}

and don't know the term R_m while differentiating with respect to R.
I really don't know after that. and I know my answer is still incomplete.
please help me.

Well, for each steady state you found, plug into the second derivative here, and see if $df/dR$ is positive or negative. One will be stable, the other unstable.
 
  • #3
a)
Can I define the first term of RHS of equation (gR/(R+R_m)) be logistic growth at a rate g with carrying capacity (R+R_m) ?
 
  • #4
grandy said:
a)
Can I define the first term of RHS of equation (gR/(R+R_m)) be logistic growth at a rate g with carrying capacity (R+R_m) ?

No, because the logistic equation would have the $R+R_m$ in the numerator, not the denominator. It would also look more like a difference: $R_m-R$, where $R_m$ is your "carrying capacity". The logistic equation is
$$\frac{dN}{dt}= \frac{r N (K-N)}{K},$$
where $K$ is the carrying capacity, and $r$ is the Malthus parameter.
 
  • #5
On the other hand, if you did a series expansion of $1/(R+R_m),$ you would get
$$ \frac{1}{R+R_m} \approx \frac{R_m-R}{R_{m}^{2}}+O(R^2).$$
That does look like a logistic term with carrying capacity $R_m$. Now it's not multiplying $R$, like it normally would, but that may be ok.
 
  • #6
b)
so my other steady state is
g-d(R+R_m) =0
R= g/d -R_m
(R*1, R*2)= (0, g/d -R_m)

From the non zero steady-state we note that g>d, otherwise R*2 <0, which is not possible because we can not have negative population density. if this does occur in practice then R*1 is the only possible steady-state where the population dies out.

Did I answer the discussion of any constraints on the model parameters for the model to admit bilogogically meaningful solutions? Do I need to talk about the term -R_m which is constant parameter I guess
 
  • #7
grandy said:
b)
so my other steady state is
g-d(R+R_m) =0
R= g/d -R_m
(R*1, R*2)= (0, g/d -R_m)

From the non zero steady-state we note that g>d,

Check your algebra here! You need
\begin{align*}
\frac{g}{d}-R_m &\ge 0 \\
\frac{g}{d} &\ge R_m \\
g &\ge d R_m.
\end{align*}

otherwise R*2 <0, which is not possible because we can not have negative population density. if this does occur in practice then R*1 is the only possible steady-state where the population dies out.

Did I answer the discussion of any constraints on the model parameters for the model to admit bilogogically meaningful solutions?

Well, there might be other things you could say (I don't know if there are or not), but this is certainly a good start.

Do I need to talk about the term -R_m which is constant parameter I guess

You've talked about it some already, in conjunction with $g$ and $d$.
 
  • #8
a)
I can rearrange the model:
dR/dt = [gR/(R+R_m)] - dR
dR/dt = gR - dR (R+R_m)

gR represents the exponential growth of population
dR represents the exponential decay of population
g is the growth rate
d is the decay rate
R is a variable and R_m is a Malthus parameter

The second term of RHS of equation - dR (R+R_m) be logistic decay at a rate d with carrying capacity R_m.
or carrying capacity (R+R_m)
Is it right thing to do?
 

FAQ: What Are the Dynamics of a Single Species Population Model?

1. What is mathematical biology?

Mathematical biology is a field that uses mathematical tools and models to study biological systems and processes. It combines principles and techniques from both mathematics and biology to gain a better understanding of how living organisms function and interact with their environment.

2. What are some applications of mathematical biology?

Some common applications of mathematical biology include studying population dynamics, disease spread and control, ecological systems, and evolutionary processes. It can also be used in fields such as genetics, neuroscience, and bioinformatics.

3. How does mathematical biology contribute to the field of biology?

Mathematical biology provides a quantitative and predictive approach to studying biological systems, which complements the traditional experimental and observational methods in biology. It allows for a deeper understanding of complex biological processes and can help identify patterns and relationships that may not be evident without mathematical analysis.

4. What skills are needed to work in mathematical biology?

A strong foundation in mathematics, especially in areas such as calculus, statistics, and differential equations, is essential for working in mathematical biology. Knowledge of biology and computer programming are also important skills to have in this field.

5. What are some current research topics in mathematical biology?

Some current research topics in mathematical biology include studying the dynamics of infectious diseases, developing models for cancer growth and treatment, understanding the mechanisms of biological pattern formation, and investigating the role of mathematical models in ecology and evolution.

Similar threads

Back
Top