What Are the Dynamics of Hitting a Helicopter with Tennis Balls in Physics?

In summary, the conversation discusses launching tennis balls to knock down a toy helicopter flying along the second floor of a 10 m high school building. The initial position of the helicopter is 4 m along the second floor line and 10 m above the ground. The conversation also mentions using the equation v = u + at to find the initial velocity of the ball launched by a friend, with the acceleration due to gravity being 10 m/s^2.
  • #1
TN17
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Homework Statement



You are sitting on the edge of your school with a tennis ball in your hand. Your friend is doing the same thing sitting on the ground leaning against the wall. You both see a toy helicopter going along the line of the second floor. You both decide to take the helicopter down. You both launch your tennis balls in such a way that you hit the helpcopter at the same time.

a) Where is the helicopter when you launch the ball?
b) Where is the helicopter when your friend launches the ball?
c) What is your friend's initial velcoity?

-School is 10 m high
-Windows are 2 m apart
-g = 10m/s2

I'm assuming that my friend is directly below me.

The Attempt at a Solution



For a) I used delta y = Viy*t + 0.5gt2 to find how long it takes for me to drop the ball. Then, if the helicopter's speed is 2m/0.5s, then it would be 4 m along the second floor line in 1 s, when I drop my ball.

For b) I'm not really sure about. I assumed my friend was directly below and had the same answer for a).

For c), I need help with.
 
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  • #2


Dear fellow forum member,

I would like to provide some input on your questions.

a) When you launch the ball, the helicopter is at a horizontal distance of 4 m along the second floor line, and at a vertical distance of 10 m above the ground (since the school is 10 m high).

b) When your friend launches the ball, the helicopter will still be at the same horizontal distance of 4 m along the second floor line, but its vertical distance will depend on the initial velocity of your friend's ball. If your friend's ball has the same initial velocity as yours, then the helicopter will still be at a vertical distance of 10 m. However, if your friend's ball has a slower initial velocity, the helicopter may have moved slightly downwards by the time the ball reaches it.

c) To find your friend's initial velocity, we can use the equation v = u + at, where v is the final velocity (in this case, 2 m/s), u is the initial velocity (what we want to find), a is the acceleration due to gravity (10 m/s^2) and t is the time it takes for the ball to reach the helicopter. We can use the same time calculated in part a) to find the initial velocity of your friend's ball.

I hope this helps! Let me know if you have any further questions.
 

FAQ: What Are the Dynamics of Hitting a Helicopter with Tennis Balls in Physics?

What is the vertical drop of a ball?

The vertical drop of a ball is the distance the ball travels in a straight line from its starting point to its endpoint when dropped from a certain height.

How is the vertical drop of a ball calculated?

The vertical drop of a ball can be calculated using the formula d = 0.5 * g * t^2, where d is the distance, g is the acceleration due to gravity (9.8 m/s^2), and t is the time the ball takes to reach the ground.

Does the mass of the ball affect its vertical drop?

Yes, the mass of a ball does affect its vertical drop. According to the formula, a heavier ball will have a larger vertical drop compared to a lighter ball when dropped from the same height.

How does air resistance affect the vertical drop of a ball?

Air resistance can have a significant impact on the vertical drop of a ball. As the ball falls, it experiences air resistance, which slows it down and reduces its vertical drop. This effect is more noticeable for objects with a larger surface area, such as a feather compared to a bowling ball.

Is the vertical drop of a ball affected by the height it is dropped from?

Yes, the height at which a ball is dropped from will affect its vertical drop. As the height increases, the ball will have more time to accelerate due to gravity, resulting in a larger vertical drop. This is represented in the formula as the variable h, which stands for the initial height.

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