What are the equations needed to solve the elastic force on an incline problem?

Solve for x (the compression)In summary, the problem involves a 2.00-kg package released on a 53.1 degree incline, with a spring attached at the bottom with a force constant of 120 N/m. The coefficients of friction are given as \mu_s = 0.40 and \mu_k = 0.20. The task is to find the speed of the package just before it reaches the spring, the maximum compression of the spring, and how close the package gets to its initial position when it rebounds back up the incline. To solve this problem, you can use the forces acting on the block, calculate the force along the incline, and use kinematics equations to find the
  • #1
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Homework Statement



A 2.00-kg package is released on a 53.1 ^\circ incline, 4.00 m from a long spring with force constant 120 N/m that is attached at the bottom of the incline View Figure . The coefficients of friction between the package and the incline are \mu_{s} \;=\; 0.40 and \mu_{k} \;=\; 0.20. The mass of the spring is negligible.

yf_Figure_7_41.jpg


1.] What is the speed of the package just before it reaches the spring?

2.] What is the maximum compression of the spring?

3.] The package rebounds back up the incline. How close does it get to its initial position?

Homework Equations





The Attempt at a Solution



I only have a limited amount of attempts to input the correct solution and I already have tried a couple different ways. I want to be guided in the right direction, not have the answer handed to me, please. Any help would be greatly appreciated. Thank you :smile:
 
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  • #2
The forces that act on the block are friction, gravity. You can calculate the force along the incline and use the kinematics equations to find the velocity (if you have the force, you'll have the acceleration).

For the compression of the spring, you have the velocity, and hence the kinetic energy. That converts into the potential energy of the spring AND the work done against friction.

For the last part, again use the same considerations to find the max height of the block.

Btw, sin53=4/5 and cos53=3/5
 
  • #3
argh. i can't seem to get the second part.
my equation is...
1/2kx^2 + (u_k)mgcos(53.1) - (1/2)(m)(v^2)=0
can anyone help?
 
  • #4
Yeah,

The equation works out to be:
[tex]0.5kx^2=4mgsin(53) - \mu _k mg*cos53*4[/tex]
 

FAQ: What are the equations needed to solve the elastic force on an incline problem?

What is elastic force on an incline?

Elastic force on an incline refers to the force exerted by a spring or elastic material when it is stretched or compressed on an inclined surface.

How is elastic force calculated on an incline?

Elastic force on an incline can be calculated using the formula F = kxsinθ, where F is the elastic force, k is the spring constant, x is the displacement of the spring, and θ is the angle of the incline.

What factors affect the elastic force on an incline?

The elastic force on an incline is affected by the spring constant, displacement of the spring, and the angle of the incline. Other factors such as the weight of the object on the spring and the coefficient of friction between the spring and the incline may also impact the elastic force.

How does an inclined surface affect elastic force?

An inclined surface can change the direction of the elastic force, causing it to act at an angle instead of purely vertical or horizontal. This can affect the magnitude and direction of the force, and therefore impact the overall motion of the object.

What are some real-world applications of elastic force on an incline?

Elastic force on an incline can be seen in many everyday objects, such as ramps, playground slides, and even exercise equipment like treadmill inclines. It is also used in engineering and physics experiments to study the behavior of elastic materials.

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