What Are the Final Velocities of Hockey Pucks After a Glancing Collision?

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In a glancing collision between two equal mass hockey pucks, puck 1 is initially at rest and is struck by puck 2 moving at 13 m/s east. After the collision, puck 1 moves at an angle of 18 degrees north of east, while puck 2 moves at an angle of 4 degrees south of east. The conservation of momentum must be applied to determine the final velocities of both pucks, but the challenge arises due to having two unknowns and only one known initial velocity. Clarification is needed on the angle notation, specifically whether [E18N] refers to 18 degrees north of east. Understanding these angles is crucial for solving the momentum equations accurately.
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Homework Statement


Two equal mass hockey pucks undergo a glancing collision. Puck 1 is initially at rest and is struck by puck 2 traveling at a velocity of 13 m/s[E]. Puck 1 travels at an angle of [E18N] after the collision. Puck 2 travels at an angle of [E4S]. Determine the final velocity of each puck.

How do I solve the problem using conservation of momentum since I only have the two initial velocities?

Homework Equations


p=mv
mv1+mv2 = mv1f+mv2f

The Attempt at a Solution


I've tried to use the equations for a perfectly elastic collision
 
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If they have equal masses, shouldn't puck 2 have a velocity of 0 and not move in any direction? I'm not sure but that is how I learned the conservation of momentum.
 
Well puck 1 has a velocity of zero and puck 2 strikes it, so in the conservation of momentum equation, v1 cancels out along with all the masses. The equation then becomes v2 = v1f + v2f. With that equation there's two unknown values and one known, so I'm not sure how to solve it from this point on.
 
Isaac0427 said:
If they have equal masses, shouldn't puck 2 have a velocity of 0 and not move in any direction? I'm not sure but that is how I learned the conservation of momentum.
That's only if it's a head-on elastic collision. This is a glancing collision.
 
member_216668 said:

Homework Statement


Two equal mass hockey pucks undergo a glancing collision. Puck 1 is initially at rest and is struck by puck 2 traveling at a velocity of 13 m/s[E]. Puck 1 travels at an angle of [E18N] after the collision. Puck 2 travels at an angle of [E4S]. Determine the final velocity of each puck.

How do I solve the problem using conservation of momentum since I only have the two initial velocities?

Homework Equations


p=mv
mv1+mv2 = mv1f+mv2f

The Attempt at a Solution


I've tried to use the equations for a perfectly elastic collision

What does angle [E18N] mean? Is it 18 degrees north of east? Is is 18 degrees east of north? Is it something else?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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