What are the forces involved in circular motion on a rotating pole?

In summary, the problem involves a 100 g bead sliding along a 80 cm string that is attached to a vertical pole at points A and C, which are 40 cm apart. The pole is rotated about its axis, causing the string to become horizontal. The task is to find the tension in the string and the speed of the bead at point B. Using the Pythagorean theorem, we can determine the lengths of the two parts of the string. To find the forces acting on point B, we need to break them into their horizontal and vertical components by considering the angle at point B. These forces include horizontal tension, tension up-and-to-the-side, and gravitational force on the bead, as well as a normal force.
  • #1
medstudent123
2
0

Homework Statement



17. A 100 g bead is free to slide along an 80 cm long piece
of string ABC. The ends of the string are attached to a
vertical pole at A and C, which are 40 cm apart. When
the pole is rotated about its axis, AB becomes
horizontal.
a. Find the tension in the string.
b. Find the speed of the bead at B.

Homework Equations



F=ma
a=v^2/r

The Attempt at a Solution



Using X^2 + (40)^2 = (80 - x )^2, I got 30 and 50 for the lengths of the two parts of the string. Now I am stuck on how to break the Forces into x and y components.
 
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  • #2
Greetings and welcome! Think about all of the forces on the point B. There's horizontal tension, there's tension up-and-to-the-side, and there's the force of gravity on the bead. Break these forces into their horizontal and vertical components by finding the angle made at point B.
 
  • #3
Ok, so... All the forces acting on the system are: gravitational force, tension in the 2 strings, which can be broken into their horizontal and vertical components. Theres normal force, right?
 

Related to What are the forces involved in circular motion on a rotating pole?

What is centripital circular motion?

Centripital circular motion refers to the type of motion that an object experiences when it moves in a circular path at a constant speed. It is caused by a centripital force that acts towards the center of the circle, keeping the object in its circular path.

What is the difference between centripital force and centrifugal force?

Centripital force is the force that acts towards the center of the circle, keeping an object in circular motion. On the other hand, centrifugal force is an imaginary force that appears to act outwards from the center of the circle, but in reality, it is just the tendency of an object to continue moving in a straight line due to its inertia.

What is the equation for calculating centripital force?

The equation for centripital force is F=mv^2/r, where F is the force, m is the mass of the object, v is the velocity, and r is the radius of the circular path. This equation shows that the centripital force increases with an increase in mass, velocity, or radius.

What is the role of centripital force in circular motion?

The role of centripital force is to constantly change the direction of an object's velocity, keeping it moving in a circular path. Without this force, the object would continue in a straight line due to its inertia, and the circular motion would not be possible.

What are some real-life examples of centripital circular motion?

Some examples of centripital circular motion include the motion of a satellite orbiting the Earth, the motion of planets around the Sun, the motion of a car around a curve, and the motion of a rollercoaster on a loop. These objects experience a centripital force that keeps them moving in a circular path.

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