- #1
Aryth1
- 39
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My problem is this:
Find the integral curves of $\textbf{V} = (log(y+z),1,-1)$.
I first set up the system:
\(\displaystyle \frac{dx}{log(y+z)} = \frac{dy}{1} = \frac{dz}{-1}\)
I have two find two curves, $u_1$ and $u_2$ that work as integral curves.
The first, and most obvious, function is $u_1(x,y,z) = y + z$. But I'm having trouble finding $u_2$. Any help is greatly appreciated!
Find the integral curves of $\textbf{V} = (log(y+z),1,-1)$.
I first set up the system:
\(\displaystyle \frac{dx}{log(y+z)} = \frac{dy}{1} = \frac{dz}{-1}\)
I have two find two curves, $u_1$ and $u_2$ that work as integral curves.
The first, and most obvious, function is $u_1(x,y,z) = y + z$. But I'm having trouble finding $u_2$. Any help is greatly appreciated!