- #1
mullets1200
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Homework Statement
A projectile's horizontal range on level ground is R =v0^2 sin2(theta)/g. At what launch angle or angles will the projectile land at half of its maximum possible range.
The Attempt at a Solution
So what i did was:
Half the range occurs when sin(2θ) = 0.5
So 2θ = arcsin(0.5)...so θ = 0.5*arcsin(0.5) = 15 (degrees)
but when i enter that in it says there is more than one answer, how do i get the other answer?