- #36
Liang Wei
- 18
- 0
Ok thanks
The maximum value of y is 12 when x is 8 + 2(14)^1/2.
The minimum value of y is -12 when x is 8 - 2(14)^1/2.
The maximum and minimum values of y can be calculated by plugging in the given value of x into the equation y = x^3 and solving for y.
Yes, the maximum and minimum values of y can be negative depending on the value of x. In this case, the maximum value of y is positive while the minimum value of y is negative.
No, there is no specific range for the values of x in this equation. As long as x is a real number, the equation will have a maximum and minimum value for y.