What Are the Momentum and Energy of Photons from a Decaying Particle?

da_warped_1
Messages
7
Reaction score
0
hi wondering if i could get a little help with this question

A particle with rest mass m has kinetic energy equal to twice its rest energy. The particle decays into 2 photons which emerge in opposite directions, one traveling in the same direction as the particle before its decay. Find expressions, in terms of m for:

(a) the momentum of the particle
(b) the energy of each of the 2 photons

thanks for any help.
 
Physics news on Phys.org
What help do you want? Where is the difficulty? In other words, what have you done on this yourself?
 
da_warped_1 said:
hi wondering if i could get a little help with this question

A particle with rest mass m has kinetic energy equal to twice its rest energy. The particle decays into 2 photons which emerge in opposite directions, one traveling in the same direction as the particle before its decay. Find expressions, in terms of m for:

(a) the momentum of the particle
(b) the energy of each of the 2 photons

thanks for any help.
For (a), start with T=E-m=2m. Solve for E and then for p.
For (b), LT each photon's energy in the particle's rest frame (k=m/2),
to the frame moving with velocity v=p/E.
 
It's given a gas of particles all identical which has T fixed and spin S. Let's ##g(\epsilon)## the density of orbital states and ##g(\epsilon) = g_0## for ##\forall \epsilon \in [\epsilon_0, \epsilon_1]##, zero otherwise. How to compute the number of accessible quantum states of one particle? This is my attempt, and I suspect that is not good. Let S=0 and then bosons in a system. Simply, if we have the density of orbitals we have to integrate ##g(\epsilon)## and we have...
Back
Top