What Are the Optimal Dimensions for a Tank to Minimize Metal Usage?

In summary, a petrochemical company is designing a cylindrical tank with hemispherical ends to be used in transporting its products. To minimize the amount of metal required, the tank should have a volume of 10,000 cubic meters and a radius of approximately 13.36 meters, resulting in a spherical shape. This is due to the fact that a sphere has the smallest possible surface area for a given volume, making it the most efficient design choice.
  • #1
Renzokuken
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1.A petrochemical company is designing a cylindrical tank with hemispherical ends to be used in transporting its products. If the volume of the tank is to be 10,000 cubic meters what dimensions should be used to minimize the amount of metal required?



2. V=pi*r^2 + 4/3*pi*r^3
SA= 4*pi*r^2+2*pi*r*h




3. 10000=pi*r^2*h+4/3*pi*r^3
solved for h=-4(pi*r^3-7500)/(3*pi*r^2)
pluged h into SA and then took the partial derivative = 8(pi*r^3-7500)/(3r^2)
r=13.36
Then i pluged r into V equation to solve for h, but h=0 and i don't think it is supposed to
 
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  • #2
Renzokuken said:
V=pi*r^2 *h + 4/3*pi*r^3
SA= 4*pi*r^2+2*pi*r*h

The fact that you get h = 0 tells you something: the figure with the smallest possible surface area for a given volume is a sphere. (The sphere is one example of what are called "minimal surfaces".) This is related to why soap bubbles are round. Since the problem posed no constraints requiring there to be a cylindrical section for the tank, h = 0 will be the correct result. (In fact, many countries use spherical tanks, appropriately supported, to store natural gas, etc.)
 
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FAQ: What Are the Optimal Dimensions for a Tank to Minimize Metal Usage?

What is Calculus 3 Minimum SA?

Calculus 3 Minimum SA refers to the concept of finding the minimum surface area of a three-dimensional object using calculus.

Why is Calculus 3 Minimum SA important?

Calculus 3 Minimum SA is important because it allows us to optimize the surface area of objects in real-world applications, such as minimizing material usage in construction or maximizing efficiency in engineering designs.

How is Calculus 3 Minimum SA calculated?

The minimum surface area is found by taking the derivative of the surface area formula, setting it equal to zero, and solving for the critical points. The critical point with the lowest surface area is the minimum surface area.

What is the difference between local and global minimum SA?

Local minimum SA refers to the lowest surface area within a small interval, while global minimum SA refers to the lowest surface area within the entire domain. In other words, global minimum is the absolute lowest point, while local minimums are lower points within a specific range.

What are some real-world applications of Calculus 3 Minimum SA?

Calculus 3 Minimum SA has various applications in fields such as engineering, architecture, and physics. It can be used to optimize the design of structures, minimize material usage, and maximize efficiency in various systems.

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